In the circuit shown, find (a) the power used by the 40 Ω resistor and (b) the power delivered to the circuit by the 12 V battery. **Circuit Diagram:** - Battery 1: 6.0 V - Battery 2: 12 V - Resistors: - R = 20 Ω - R = 40 Ω - R = 10 Ω - R = 80 Ω - R = 50 Ω **Details:** - The circuit consists of two batteries and five resistors connected in a network. - The resistors are connected in a combination of series and parallel configurations. - To solve the problem, you may need to use principles from Ohm's Law and the Power formula: - **Ohm’s Law:** V = IR - **Power Formula:** P = IV = I²R = V²/R **Analysis Steps:** 1. Calculate the current in each section of the circuit by analyzing the circuit configuration. 2. Use the current to find the power across the specified 40 Ω resistor. 3. Determine the total power supplied by the 12 V battery using the power formula. By following these steps, you can determine the power distribution in the circuit.
In the circuit shown, find (a) the power used by the 40 Ω resistor and (b) the power delivered to the circuit by the 12 V battery. **Circuit Diagram:** - Battery 1: 6.0 V - Battery 2: 12 V - Resistors: - R = 20 Ω - R = 40 Ω - R = 10 Ω - R = 80 Ω - R = 50 Ω **Details:** - The circuit consists of two batteries and five resistors connected in a network. - The resistors are connected in a combination of series and parallel configurations. - To solve the problem, you may need to use principles from Ohm's Law and the Power formula: - **Ohm’s Law:** V = IR - **Power Formula:** P = IV = I²R = V²/R **Analysis Steps:** 1. Calculate the current in each section of the circuit by analyzing the circuit configuration. 2. Use the current to find the power across the specified 40 Ω resistor. 3. Determine the total power supplied by the 12 V battery using the power formula. By following these steps, you can determine the power distribution in the circuit.
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In the circuit shown, find (a) the power used by the 40 ohm resister and (b) the power delivered to the circuit by the 12 v battery.
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