Four resistors are connected to a battery with a terminal voltage of 12 V, as shown in the figure below. (Assume R, - 36.0 N and R, = 78.0 2.) R 50.0 N R2 20.0 N 12 V (a) How would you reduce the circuit to an equivalent single resistor connected to the battery? Use this procedure to find the equivalent resistance of the circuit. Ω (b) Find the current delivered by the battery to this equivalent resistance. A (c) Determine the power delivered by the battery. (d) Determine the power delivered to the 50.0-2 resistor.
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- Four resistors are connected to a battery with a terminal voltage of 12 V, as shown in the figure below. (Assume R1 = 27.0 Ω and R2 = 70.0 Ω.) (a) How would you reduce the circuit to an equivalent single resistor connected to the battery? Use this procedure to find the equivalent resistance of the circuit. ____ Ω(b) Find the current delivered by the battery to this equivalent resistance. ____ A(c) Determine the power delivered by the battery. ____ W(d) Determine the power delivered to the 50.0-Ω resistor. ____ WSee the above circuit diagram to answer the question. The battery voltage is V = 66.1 V; R1 = 126 Ohms; R2 = 122 Ohms; R3 = 190 Ohms; R4 = 71 Ohms; R5 = 198 Ohms; and R6 = 120 Ohms. How much current flows through resistor R3? 0.144 A 0.170 A 0.093 A 0.195 AConsider the network of four resistors shown in the diagram, where R1 = 1 Ω, R2 = 5 Ω, R3 =2Ω,andR4 =6Ω. . The resistors are connected to a battery with an emf V. (a) What is the current flowing out of the battery if the emf is 12 V? (B) What is the voltage difference across the resistor R1? (C) What is the rate of Ohmic dissipation for resistor R2?
- a) What is the terminal voltage (in V) of a large 1.35 V carbon-zinc dry cell used in a physics lab to supply 1.80 A to a circuit, if the cell's internal resistance is 0.300 Ω? b) How much electrical power (in W) does the cell produce? and c) What power (in W) goes to its load?The figure below shows five resistors and two batteries connected in a circuit. What are the currents I,, I2, and I3? (Consider the following values: R, = 1.08 0, R2 = 2.20 0, R3 = 3.18 0, R4 = 4.04 0, R5 = 6.06 0. Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign. Indicate the direction with the sign of your answer.) A A I3 = A Rs R3 12.0 V R2 9.00 V R1Consider the circuit shown in the figure below, where R1 = 5.00 Ω, R2 = 9.00 Ω, and 3 = 11.0 V. (a) Find the voltage (in V) across R1. (b) Find the current (in A) in R1.
- The figure below shows five resistors and two batteries connected in a circuit. What are the currents I1, I2, and I3? (Consider the following values: R1 = 1.20 Ω, R2 = 2.16 Ω, R3 = 3.19 Ω, R4 = 4.18 Ω, R5 = 6.18 Ω. Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign. Indicate the direction with the sign of your answer.)I1=?I2=?I3=?Consider the circuit, as shown in the figure above. R1 = 10.0 ohm, R2 = 11.0 ohm, R3 = 4.00 ohm, R4 = 5.00 ohm, R5 = 21.0 ohm and V = 26.0 V. Calculate the magnitude of the current in the R5 = 21.0 ohm resistor. Calculate the magnitude of the potential difference between points a and b.The figure below shows five resistors and two batteries connected in a circuit. What are the currents I, I2, and Ig? (Consider the following values: R₁ - 1.200, R₂ =2.18 Q, Rg-3.13 Q, R44.100, Rs 6.20 0. Due to the nature of this problem, do not use rounded intermediate values in your calculations including answers submitted in WebAssign. Indicate the direction with the sign of your answer.) Need Help? 12.0 V 9.00 V Read It R₂ www R₁
- The circuit below contains two real batteries, each having significant internal resistance. Battery #1 has an EMF of 6.00 V and an internal resistance of 1.00 ohm. Battery #2 has an EMF of 12.00 V and an internal resistance of 2.00 ohms. These two batteries are connected in series with two resistors R, = 6.00 ohms and R,= 3.00 ohms. ri d (6.00,V) (1.00 0) R1 (6.00 N) R2 (3.00 N) a r2 E2 (2.00 Q) (12.00 V) 18. The current in the 12.00 Volt battery is equal to C. 0.500 A. A. 0.750 A. B. 1.00 A. D. 2.00 A. E. 1.50 A. 19. The potential difference across the terminals of battery #1 from point C to point d is equal to C. 7.00 V. A. 5.50 V. B. 6.00 V. D. 5.00 V. E. 6.50 V. 20. The potential difference across the terminals of battery #2 from point a to point b is equal to C. 13.00 V. A. 14.00 V. В. 10.00 V. D. 11.0 V. E. 12.00 V.For the circuit shown in the figure, calculate the following. (Assume E = 7.56 V and R 5.40 N.) 12.0 V + 4.00 N 2.00 Ω R (a) the current in the 2.00-n resistor (Enter the magnitude.) A (b) the potential difference between points a and b, AV = V, - V, VConsider the circuit shown in the figure below. (Let R = 28.0 M.) 25.0 V 5.00 Ω 10.0 Ω www 10.0 Ω W ww www 5.00 Ω (a) Find the current in the 28.0- resistor. A b www R (b) Find the potential difference between points a and b. V