Record your measurements below. Number on ball and launcher used Height readings 65.52. 53 56. 57. 53 58. 55. 60 56 60 63 Vi= √2gharg vi= 33.61 Average Height 57. Standard Deviation of height3.746 √2(9.81)(57.6) 2 Average Initial Speed Max and Min speeds. 54 61 57 33.61 Calculate the average initial speed of the projectile (Show your work). Also determine the range of speeds using +/- 20 of the average height. Show all work. 51 61 60 59. 61 Vmax = √aghmax адитах vmin=Vaghmin
Record your measurements below. Number on ball and launcher used Height readings 65.52. 53 56. 57. 53 58. 55. 60 56 60 63 Vi= √2gharg vi= 33.61 Average Height 57. Standard Deviation of height3.746 √2(9.81)(57.6) 2 Average Initial Speed Max and Min speeds. 54 61 57 33.61 Calculate the average initial speed of the projectile (Show your work). Also determine the range of speeds using +/- 20 of the average height. Show all work. 51 61 60 59. 61 Vmax = √aghmax адитах vmin=Vaghmin
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Question
what is the max and min speed?
Transcribed Image Text:Record your measurements below.
Number on ball and launcher used
Height readings
65.52.
53
56. 57. 53
58. 55.
60
56 60
63
Vi= √2gharg
vi= 33.61
Average Height 57.
Standard Deviation of height3.746
√2(9.81)(57.6)
2
Average Initial Speed
Max and Min speeds.
54
61
57
33.61
Calculate the average initial speed of the projectile (Show your work). Also determine the
range of speeds using +/- 20 of the average height. Show all work.
51
61
60
59. 61
Vmax = √aghmax
адитах
vmin=Vaghmin
Expert Solution
Step 1 A
Solution:
Hmax = h + 2σ
Hmax = 57.6 + (2 x 3.746)
Hmax = 65.092
Vmax = √(2 x 9.8 x 65.092)
Vmax = 35.718
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