_____ km/s______ hr What is the orbital velocity and period of a ring particle at the outer edge of Saturn's A ring? (Note: The radius of the edge of the A ring isGM136,500 km. Hint: Use the formula for orbital velocity, V̟ =rorbital velocitykm/speriodhr

Given: Gravitational Constant, G=6.67×10-11 Nm2/kg2Mass of Saturn, M=5.683×1026 kgRadius, r=136500×103 m The orbital speed of an astronomical body or object is the speed at which it orbits around the barycenter or if one object is significantly more massive than the other entities in the system; the speed is relative to the most massive body's center of mass.a) The expression of the orbital velocity is as follows: vC=GMr ....(1) Substitute the value in equation (1). vC=6.67×10-11Nm2/kg25.683×1026kg136500×103mvC=37.90×1015Nm2/kg136500×103mvC=0.0277×1010Nm/kgvC=0.1664×105m/s The orbital velocity is 16.64 km/s. b) The expression of the time period is as follows: T=2πrvC ,,,,, (2) Substitute the value in equation (2). T=2×3.14×136500×103m0.1664×105m/sT=857220×103m0.1664×105m/sT=51515.625s The time period is 14.30 hr.

Answered: What is the orbital velocity and period…

What is the orbital velocity and period of a ring particle at the outer edge of Saturn's A ring? (Note: The radius of the edge of the A ring is GM 136,500 km. Hint: Use the formula for orbital velocity, V = V orbital velocity km/s period hr