Prove using the mirror equation (eq. 1) and magnification equation (eq. 2) the optical data gathered when an object is placed at f using a concave mirror? Given: f= 4; ho = 2; do = 4 Mirror Equation (eq. 1) Magnification Equation (eq. 2) di hi m =- = 1+1=7 do di do ho
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- A glass sphere (n = 1.50) with a radius of 16.0 cm has a tiny air bubble 4.30 cm above its center. The sphere is viewed looking down along the extended radius containing the bubble. What is the apparent depth of the bubble below the surface of the sphere? 7.936 Apply the equation relating the object distance, image distance, and radius of curvature for a spherical refracting surface. cm Need Help? Read It Master ItIP The greatest refractive power a patient's eyes can produce is 43.7 diopters. n/a Submit Submitted, grade pending Part C Previous Answers If this patient is nearsighted, find the far point. If this person is farsighted, find the near point. N = 2.3 Submit V— ΑΣΦ www Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining ? Review cmA diverging lens has a focal length of magnitude 17.6 cm. (a) For an object distance of 44.0 cm, determine the following. What are the image distance and image location with respect to the lens? (Give the magnitude of the distance in cm.) image distance cmimage location ---Select--- behind the lens in front of the lens Is the image real or virtual? ---Select--- real virtual What is the magnification? Is the image upright or inverted? ---Select--- upright inverted (b) For an object distance of p2 = 26.4 cm, determine the following. What are the image distance and image location with respect to the lens? (Give the magnitude of the distance in cm.) image distance cmimage location ---Select--- behind the lens in front of the lens Is the image real or virtual? ---Select--- real virtual What is the magnification? Is the image upright or inverted? ---Select--- upright inverted (c) For an object distance of p3 = 13.2 cm, determine the following. What are the image…
- Could you please explain me why is not in front but behind? How is it possible that a divergent lens can form a real immage, shouldn t be impossible?Y; H CONCAVE MIRROR Yo ← Di F Do 14+ f The figure shows light rays reflected from a concave spherical mirror. The focal length is f 0.9 cm and the object (the upright arrow) has = 1.620 cm and yo = 1 cm. Determine the lengths D; and yi. DoPlease help me to prove this equation in this picture below
- A concave mirror on the left is separated from a converging lens on the right by 50 cm. An object is placed 20.0 cm to the right of a concave mirror with focal length 12.0 cm and 30.0 cm to the left of a converging lens with focal length 10.0 cm, what would be the magnification factor created by both the mirror and lens. 1. do not have enough information to do a calculation 2.one 3.two 4. none of the given choicesIn a concave mirror, given do=8, f=4, and ho=2, what would be the d; & h; and magnification value? Is the image enlarged, reduced, or just the same? Mirror Equation 1 1 1 + = do di f Magnification Equation di m=- haiting do ho