1, = -10.0 cm 1- -20.0 cm real object 10.0 cm 10.0 cm t Consider the optical system comprised of two thin lenses shown above. Find the final image position relative to the principle plane of the seond lens, system lateral magnification and describe the final image.
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- A student wears eyeglasses of power P = -1.5 diopter to correct nearsightedness. The glasses are designed to be worn d = 2.3 cm in front of the eye. Input an expression for the far point the student can see without correction, do. Numerically, what is the distance in meters?A2.71-cm-high insect is 1.24 m from a 135-mm-focal-length lens. Where is the image? O in front the lens O behind the lens How high is the image? Express your answer with the appropriate units. ? h = Value Units4.To measure the focal length of a diverging lens, a converging lens is placed in contact with it as shown to the right. The sun's focused by this Image point made by first lens (object point for second lens) are rays combination at a point 28.5 cm behind Image made by second lens the lenses. If the converging lens has a focal length fc of 16 cm, what is the focal length of the diverging lens? (final image) fc -fr =28.5 cm
- Problem 5: Rachel has good distant vision but has a touch of presbyopia. Her near point is 0.60 m. When she wears +2.0 D reading glasses, a. What is her near point? b. What is her far point? Normal Lens Thickened to Focus on Near Objects Presbyopia Lens Hardened by age and Unable to Change Shape Presbyopia Corrected Corrected with Eyeglasses or contact lenses Image on the Retina Image Behind the Retina Image on the Retinacalculate final image location w/ respect to second lens and calculate magnification factor using double lens systemA plano-concave lens for an underwater camera is shown below. It's diopter under water is -8.33. The radius of curvature of its front surface is 8 cm. Assuming that the index of fraction ofwater is 1.33, what is the index of fraction of the substance of which this lens it is made? a. 2.00 b. 1.81 c. 1.52 d. 1.67