EX (1)-lec 31 F(t) == t - F(w) = f(t) eve dt 5² Integration by Parts with s u=t du=dt and dr=ecut de ⇒V= F (w) = = [[ -iwt. Faw) = ² = { [+] - [_(²)] + 2 } T iw --1/₂ -iwt [4:24 +0 p -1 wt F -iw Th -iw I F()주)글 ( ) -iw ete K (-) iw (-) (w iw (-)- []} te F(w) = ²/_ (_T Cos WI ) + 2i t-wz -iw Integration by Parts: Su dv = uv-Sv du 1_1-1² w² F (w) = = {-TW Gs WT - 2012 Sin WT }} w² F (W) = 21 (s WT - 44 Sin WT 4i TW² 2 iw = iw I (²7) -e ²7-2 ان؟ e = Cos 0 + 1 Sin Sin 8= -iw -io 1² w² 21 10 18 = Cos 8-i Sint Cos 9 = 2 + 10 → 2 Ans. -21

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
can be clearly resolved
EX (1)-lec 31 F(t) == t
-
F(w) = f(t) eve dt
5²
Integration by Parts with s
u=t du=dt and dr=ecut de ⇒V=
F (w) = = [[
-iwt.
Faw) = ² = { [+] - [_(²)] + 2 }
T
iw
--1/₂
-iwt
[4:24 +0
p
-1
wt
F
-iw
Th
-iw I
F()주)글 ( )
-iw
ete
K
(-) iw (-) (w iw (-)-
[]}
te
F(w) = ²/_ (_T Cos WI ) + 2i
t-wz
-iw
Integration by Parts:
Su dv = uv-Sv du
1_1-1² w²
F (w) = = {-TW Gs WT - 2012 Sin WT }}
w²
F (W) = 21 (s WT - 44 Sin WT
4i
TW²
2
iw = iw I
(²7)
-e
²7-2
ان؟
e
= Cos 0 + 1 Sin Sin 8=
-iw
-io
1² w²
21
10
18
= Cos 8-i Sint Cos 9 = 2 + 10
→
2
Ans.
-21
Transcribed Image Text:EX (1)-lec 31 F(t) == t - F(w) = f(t) eve dt 5² Integration by Parts with s u=t du=dt and dr=ecut de ⇒V= F (w) = = [[ -iwt. Faw) = ² = { [+] - [_(²)] + 2 } T iw --1/₂ -iwt [4:24 +0 p -1 wt F -iw Th -iw I F()주)글 ( ) -iw ete K (-) iw (-) (w iw (-)- []} te F(w) = ²/_ (_T Cos WI ) + 2i t-wz -iw Integration by Parts: Su dv = uv-Sv du 1_1-1² w² F (w) = = {-TW Gs WT - 2012 Sin WT }} w² F (W) = 21 (s WT - 44 Sin WT 4i TW² 2 iw = iw I (²7) -e ²7-2 ان؟ e = Cos 0 + 1 Sin Sin 8= -iw -io 1² w² 21 10 18 = Cos 8-i Sint Cos 9 = 2 + 10 → 2 Ans. -21
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