Activity: A dropped object has a flight time of 0.62 s. How much distance did the object cover in this time and how much speed was gained by it?
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A: a. The displacement of the ball is 5.00 m. therefore, s=ut+12at2u=0,a=gs=0t+12gt25.00 m=+1210…
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Q: How do you solve this question?
A: a) velocity=v =3.1m/s height s=4.5m from newton first equation S=ut+12gt2 u=0…
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A: Question 40 is considered for the answer. Let us calculate the velocity of the ball at its maximum…
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