ACTIVITY 3 b. P(x28) P(Xz3) = P(x=3)+ PCX)= a) + P(X=10)1 P(X=11) * PC* + 12), +就t宽+或+元 P(x) %3D 2. 3. 2. 5. %3D 36 2. 36 36 15 3. 36 Thus, the value of P(xZ8),12 %3D 4. 34 34 C. Find PCx<7) P (X S7)= P (x=7) t PCX7 6)+PCX -5) + P(X=H)+ PCx=3) + PLX=0) 4 3 8 36 36 21 36 ROKEJE NON rupree 36 %3D 3 10 thus, the valme of P(xS7) = 2 ろい 1. 12 48
ACTIVITY 3 b. P(x28) P(Xz3) = P(x=3)+ PCX)= a) + P(X=10)1 P(X=11) * PC* + 12), +就t宽+或+元 P(x) %3D 2. 3. 2. 5. %3D 36 2. 36 36 15 3. 36 Thus, the value of P(xZ8),12 %3D 4. 34 34 C. Find PCx<7) P (X S7)= P (x=7) t PCX7 6)+PCX -5) + P(X=H)+ PCx=3) + PLX=0) 4 3 8 36 36 21 36 ROKEJE NON rupree 36 %3D 3 10 thus, the valme of P(xS7) = 2 ろい 1. 12 48
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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e. Find P(3 less than or equal to X less than or equal to 10)?
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