ACTIVITY 3 b. P(x28) P(Xz3) = P(x=3)+ PCX)= a) + P(X=10)1 P(X=11) * PC* + 12), +就t宽+或+元 P(x) %3D 2. 3. 2. 5. %3D 36 2. 36 36 15 3. 36 Thus, the value of P(xZ8),12 %3D 4. 34 34 C. Find PCx<7) P (X S7)= P (x=7) t PCX7 6)+PCX -5) + P(X=H)+ PCx=3) + PLX=0) 4 3 8 36 36 21 36 ROKEJE NON rupree 36 %3D 3 10 thus, the valme of P(xS7) = 2 ろい 1. 12 48

A First Course in Probability (10th Edition)
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ISBN:9780134753119
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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d. Find the probability that X takes an even value.

e. Find P(3 less than or equal to X less than or equal to 10)?

ACTIVITY 3
P(x)
b. P(X28)
a.
P(XZ8)=P(x=8)+ PCx)= 9) + P (x=10)1 PCX=11)* PC+ + 12)
2.
5.
36
3.
36
AVTIVITOA
3
36
36
36
%3D
36
15
3.
36
thus, the value of P(xZ8)512.00Sno ONNITHO
こ
4.
34
1.
C. Find P.(x<7),
p (X <7)= P(x=7) t P(XF 6) + PCX -5) + P (x=4)+ PCX = 3) + PLX=2)
34
317
2739DUE
3.
B4 34 るし
36
34
4.
36
21
36
9
ニ
3
10
子
12
thus, the vame of P(x<7) = Te
王
2.
34
12
1.
36
2.
「ト
Transcribed Image Text:ACTIVITY 3 P(x) b. P(X28) a. P(XZ8)=P(x=8)+ PCx)= 9) + P (x=10)1 PCX=11)* PC+ + 12) 2. 5. 36 3. 36 AVTIVITOA 3 36 36 36 %3D 36 15 3. 36 thus, the value of P(xZ8)512.00Sno ONNITHO こ 4. 34 1. C. Find P.(x<7), p (X <7)= P(x=7) t P(XF 6) + PCX -5) + P (x=4)+ PCX = 3) + PLX=2) 34 317 2739DUE 3. B4 34 るし 36 34 4. 36 21 36 9 ニ 3 10 子 12 thus, the vame of P(x<7) = Te 王 2. 34 12 1. 36 2. 「ト
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