The probability distribution of the number of high-definition (HD) televisions per household in a small town is shown. Find the area of each bar of the accompanying histogram. Then find the sum of the areas. Interpret the results. X 1 P(x) 0.257 Click here to view the histogram. 0 0.027 2 0.337 3 or more 0.379 The area of bar 0 is 0.027, bar 1 is 0.257, bar 2 is 0.337 and bar 3+ is 0.379. The sum of the areas is equal to 1. (Type integers or decimals. Do not round.) Choose the correct interpretation below. O A. The area of each of the bars equals the probabilities due to luck. The sum is 1 because the sum of the areas must be 1. O B. The area is found by multiplying the number of televisions in each category by the total number of televisions. The sum is 1 because the sum of the areas must be 1. OC. The area of each of the bars is the probability of each outcome because the width is 1. The sum is 1 because all the probabilities should add up to 1. O D. The area is found by P(x) multiplied by x. The sum is 1 because all the probabilities should add up to 1.
The probability distribution of the number of high-definition (HD) televisions per household in a small town is shown. Find the area of each bar of the accompanying histogram. Then find the sum of the areas. Interpret the results. X 1 P(x) 0.257 Click here to view the histogram. 0 0.027 2 0.337 3 or more 0.379 The area of bar 0 is 0.027, bar 1 is 0.257, bar 2 is 0.337 and bar 3+ is 0.379. The sum of the areas is equal to 1. (Type integers or decimals. Do not round.) Choose the correct interpretation below. O A. The area of each of the bars equals the probabilities due to luck. The sum is 1 because the sum of the areas must be 1. O B. The area is found by multiplying the number of televisions in each category by the total number of televisions. The sum is 1 because the sum of the areas must be 1. OC. The area of each of the bars is the probability of each outcome because the width is 1. The sum is 1 because all the probabilities should add up to 1. O D. The area is found by P(x) multiplied by x. The sum is 1 because all the probabilities should add up to 1.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Probability Distribution of HD Televisions Per Household
The probability distribution of the number of high-definition (HD) televisions per household in a small town is shown below.
#### Table
| x | 0 | 1 | 2 | 3 or more |
|----------|---------|--------|--------|-----------|
| P(x) | 0.027 | 0.257 | 0.337 | 0.379 |
Click here to view the histogram.
### Calculation
To determine the area of each bar in the accompanying histogram, we consider the following:
- The area of bar 0 is 0.027.
- The area of bar 1 is 0.257.
- The area of bar 2 is 0.337.
- The area of bar 3+ is 0.379.
### Sum of the Areas
The sum of the areas equals:
\[ 0.027 + 0.257 + 0.337 + 0.379 = 1 \]
### Interpretation
Now, choose the correct interpretation of the results:
- **A.** The area of each of the bars equals the probabilities due to luck. The sum is 1 because the sum of the areas must be 1.
- **B.** The area is found by multiplying the number of televisions in each category by the total number of televisions. The sum is 1 because the sum of the areas must be 1.
- **C.** The area of each of the bars is the probability of each outcome because the width is 1. The sum is 1 because all the probabilities should add up to 1.
- **D.** The area is found by P(x) multiplied by x. The sum is 1 because all the probabilities should add up to 1.
___
**Note:** The correct response is **C**. The area of each bar in a probability histogram represents the probability of each outcome, and the sum of these probabilities must add up to 1.
For more in-depth learning, visit our additional resources on probability distributions and histograms.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F09dd8e29-942c-4a28-8d6e-4fa3e84656fc%2F62d39ccb-5e4b-4ca7-8655-6b4c48b9619f%2F116tmb5_processed.png&w=3840&q=75)
Transcribed Image Text:### Probability Distribution of HD Televisions Per Household
The probability distribution of the number of high-definition (HD) televisions per household in a small town is shown below.
#### Table
| x | 0 | 1 | 2 | 3 or more |
|----------|---------|--------|--------|-----------|
| P(x) | 0.027 | 0.257 | 0.337 | 0.379 |
Click here to view the histogram.
### Calculation
To determine the area of each bar in the accompanying histogram, we consider the following:
- The area of bar 0 is 0.027.
- The area of bar 1 is 0.257.
- The area of bar 2 is 0.337.
- The area of bar 3+ is 0.379.
### Sum of the Areas
The sum of the areas equals:
\[ 0.027 + 0.257 + 0.337 + 0.379 = 1 \]
### Interpretation
Now, choose the correct interpretation of the results:
- **A.** The area of each of the bars equals the probabilities due to luck. The sum is 1 because the sum of the areas must be 1.
- **B.** The area is found by multiplying the number of televisions in each category by the total number of televisions. The sum is 1 because the sum of the areas must be 1.
- **C.** The area of each of the bars is the probability of each outcome because the width is 1. The sum is 1 because all the probabilities should add up to 1.
- **D.** The area is found by P(x) multiplied by x. The sum is 1 because all the probabilities should add up to 1.
___
**Note:** The correct response is **C**. The area of each bar in a probability histogram represents the probability of each outcome, and the sum of these probabilities must add up to 1.
For more in-depth learning, visit our additional resources on probability distributions and histograms.
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