Active Dosage Form Raw Materials Actual Yield Formulation Packaging Ingredient Calcium carbonate 1.75kgs calcium carbonate 160mg per 10mL Oral 2 kgs calcium oxide and 1.75 kg H2O 100mL per bottle Suspension suspension Which among the three given balanced equations is the BEST to compute for the Percent composition by mass of each compound, Mass to Mass Stoichiometry Calculation, Limiting Reagent, Excess Reagent, Amount (g) in excess, Percent Yield, and Number of dosage form and packaging that can be produced from stoichiometric calculation?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Active
Dosage
Form
Packaging
Raw Materials
Actual Yield Formulation
Ingredient
2 kgs calcium oxide and
1.75 kg H20
1.75kgs
calcium
carbonate
160mg per
10mL
100mL per
bottle
Calcium
Oral
carbonate
Suspension
suspension
Which among the three given balanced equations is the BEST to compute for the
Percent composition by mass of each compound, Mass to Mass Stoichiometry
Calculation, Limiting Reagent, Excess Reagent, Amount (g) in excess, Percent Yield, and
Number of dosage form and packaging that can be produced from stoichiometric
calculation?
i.
CaO + H,0 - Ca(OH)2
ii.
Ca(OH), + CO2
→ CaCO; + H2O
iii.
СаО + H,О + CO, >
→ CaCO; + H,0
Transcribed Image Text:Active Dosage Form Packaging Raw Materials Actual Yield Formulation Ingredient 2 kgs calcium oxide and 1.75 kg H20 1.75kgs calcium carbonate 160mg per 10mL 100mL per bottle Calcium Oral carbonate Suspension suspension Which among the three given balanced equations is the BEST to compute for the Percent composition by mass of each compound, Mass to Mass Stoichiometry Calculation, Limiting Reagent, Excess Reagent, Amount (g) in excess, Percent Yield, and Number of dosage form and packaging that can be produced from stoichiometric calculation? i. CaO + H,0 - Ca(OH)2 ii. Ca(OH), + CO2 → CaCO; + H2O iii. СаО + H,О + CO, > → CaCO; + H,0
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