ACT Scores A survey of 1000 students nationwide showed a mean ACT score of 21.4. A survey of 500 Tennessee scores showed a mean of 21.3. If the population standard deviation in each case is 3, can we conclude the national average is greater than the Tennessee average? Use a=0.10 and use μ₁ for nationwide mean ACT score.

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**ACT Scores Analysis**

A survey of 1,000 students nationwide showed a mean ACT score of 21.4. A survey of 500 Tennessee scores showed a mean of 21.3. If the population standard deviation in each case is 3, can we conclude the national average is greater than the Tennessee average? Use α = 0.10 and use μ₁ for the nationwide mean ACT score.

**Explanation:**
This text is part of a statistical hypothesis testing problem. The aim is to determine if there is a significant difference between the national average ACT score and the average ACT score from Tennessee. The parameters include:
- Nationwide sample size: 1,000 students
- Tennessee sample size: 500 students
- National mean ACT score: 21.4
- Tennessee mean ACT score: 21.3
- Population standard deviation: 3
- Significance level (α): 0.10

To conduct this test, you would typically use a z-test for comparing means, given the population standard deviation is known and sample sizes are large.
Transcribed Image Text:**ACT Scores Analysis** A survey of 1,000 students nationwide showed a mean ACT score of 21.4. A survey of 500 Tennessee scores showed a mean of 21.3. If the population standard deviation in each case is 3, can we conclude the national average is greater than the Tennessee average? Use α = 0.10 and use μ₁ for the nationwide mean ACT score. **Explanation:** This text is part of a statistical hypothesis testing problem. The aim is to determine if there is a significant difference between the national average ACT score and the average ACT score from Tennessee. The parameters include: - Nationwide sample size: 1,000 students - Tennessee sample size: 500 students - National mean ACT score: 21.4 - Tennessee mean ACT score: 21.3 - Population standard deviation: 3 - Significance level (α): 0.10 To conduct this test, you would typically use a z-test for comparing means, given the population standard deviation is known and sample sizes are large.
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