Answered: ° Acetyl CoA 2e COA Decaboration H,CH,C…

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° Acetyl CoA 2e COA Decaboration H,CH,C Taler to CA H3C S-COA Oxidation གསའི་ H3C Pyruvate -

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter18: Carboxylic Acids

Section: Chapter Questions

Problem 18.53P

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Acetolactate synthase transfers the acyl group of pyruvate to alpha-ketobutyrate. This is the first step in the biosynthesis of the amino acid isoleucine. Propose a mechanism for this reaction.
a Lactate dehydrogenase H H3C-C-coO- ОН ooc-C-CH3 L-(+)-Lactase Pyruvate This is a(an) b Creatine kinase CH3 O CH3 O H2N, АТР ADP NH2 NH2 Adenosine triphosphate Adenosine diphosphate Creatine Phosphocreatine This is a(an)
Oxaloacetate + ADP + Pi + H+ ---> Pyruvate + ATP + HCO3- ΔGo’ = 13.91 kJ/mol Lactate + NAD+ ---> Pyruvate + NADH + H+ ΔGo’ = 25.12 kJ/mol Oxaloacetate + GTP ---> Phosphoenolpyruvate + GDP + CO2 ΔGo’ = -28.40 kJ/mol HCO3- + H+ ---> CO2 + H2O ΔGo’ = -41.45 kJ/mol GDP + ATP ---> GTP + ADP ΔGo’ = -0.003 kJ/mol _________________________________________________________________________________________________________________ Lactate + NAD+ + 2ATP + H2O ---> Phosphoenolpyruvate + NADH + 2ADP + Pi + 3H+ From the above information, calculate theΔGo’ for the overall reaction shown…
Oxaloacetate + ADP + Pi + H+ ---> Pyruvate + ATP + HCO3- ΔGo’ = 13.91 kJ/mol Lactate + NAD+ ---> Pyruvate + NADH + H+ ΔGo’ = 25.12 kJ/mol Oxaloacetate + GTP ---> Phosphoenolpyruvate + GDP + CO2 ΔGo’ = -28.40 kJ/mol HCO3- + H+ ---> CO2 + H2O ΔGo’ = -41.45 kJ/mol GDP + ATP ---> GTP + ADP ΔGo’ = -0.003 kJ/mol _________________________________________________________________________________________________________________ Lactate + NAD+ + 2ATP + H2O ---> Phosphoenolpyruvate + NADH + 2ADP + Pi + 3H+ From the above information, calculate the Keq’ for the overall reaction shown…
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N-NHPH CHO CH2OH H- C=N-NHPH Но- -H- 3 equiv Но- -H- 3 equiv Но- PHNHNH2 PHNHNH, H- H- OH H- -O- H- H- -HO- H- -HO- ČH2OH ČH2OH ČH2OH D-glucose osazone D-fructose + NH3 + PHNH2 + 2 H20 The final step in the formation of the osazone from glucose is the reaction of the keto imine with 2 equivalents of phenylhydrazine to yield the osazone plus ammonia. This reaction involves the following intermediate steps: 1. Addition of phenylhydrazine to the imine and proton transfer to yield intermediate 1; 2. Elimination of ammonia to yield phenylhydrazone 2; 3. Addition of phenylhydrazine to the ketone to yield tetrahedral intermediate 3; 4. Proton transfer yields carbinolamine 4; 5. Elimination of water yields the final product osazone. Write out the mechanism on a separate sh of paper and then draw the structure of tetrahedral intermediate 3. NH НО- -H H- -ОН H- -ОН ОН Glucose keto imine Previous Ne
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