Accounting for viscous drag and fuel-burning, the one-dimensional equation of motion for a rocket- propelled vehicle travelling along a horizontal surface is 1 PACv² – k- dt dv dm m dt where (in Sl units) p = 1.2 is the density of air, A = 1 is the effective frontal area of the vehicle, C, = 0.25 is the drag coefficient and k = 3000 is the rocket's thrust coefficient. Furthermore, if the mass of the vehicle after fuelling is 3000 kg and the fuel burn rate is a linear 6 kg s-1, then one may write m = 3000 – 6t Substitute this expression for m and the values of p, A, C, and k into the differential equation above to show that dv_ 18,000 – 0.15v dt 3000 – 6t and solve this numerically using Euler's method in MATLAB with the initial condition v(0) = 0 and the step size h = 5 (include a screenshot), plot a fully labelled graph of your results for 0 sts 200 s, state the recursion relations (linking t, to tn-1 and v, to vn-1) you used to perform your numerical solution; and, state the maximum speed that the vehicle is able to reach in the interval 0 st S 200 s.

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 4
Accounting for viscous drag and fuel-burning, the one-dimensional equation of motion for a rocket-
propelled vehicle travelling along a horizontal surface is
dv
1
dm
m
dt
PAC,v² – k-
dt
where (in Sl units) p = 1.2 is the density of air, A = 1 is the effective frontal area of the vehicle, C, =
0.25 is the drag coefficient and k = 3000 is the rocket's thrust coefficient. Furthermore, if the mass of
the vehicle after fuelling is 3000 kg and the fuel burn rate is a linear 6 kg s-, then one may write
m = 3000 – 6t
Substitute this expression for m and the values of p, A, C, and k into the differential equation
above to show that
dv
18,000 – 0.15v?
3000 – 6t
dt
and solve this numerically using Euler's method in MATLAB with the initial condition v(0) = 0
and the step size h = 5 (include a screenshot),
• plot a fully labelled graph of your results for 0 <t< 200 s,
state the recursion relations (linking tn to tn-1 and vn to vn-1) you used to perform your
numerical solution; and,
state the maximum speed that the vehicle is able to reach in the interval 0 <t < 200 s.
(B)
Transcribed Image Text:Question 4 Accounting for viscous drag and fuel-burning, the one-dimensional equation of motion for a rocket- propelled vehicle travelling along a horizontal surface is dv 1 dm m dt PAC,v² – k- dt where (in Sl units) p = 1.2 is the density of air, A = 1 is the effective frontal area of the vehicle, C, = 0.25 is the drag coefficient and k = 3000 is the rocket's thrust coefficient. Furthermore, if the mass of the vehicle after fuelling is 3000 kg and the fuel burn rate is a linear 6 kg s-, then one may write m = 3000 – 6t Substitute this expression for m and the values of p, A, C, and k into the differential equation above to show that dv 18,000 – 0.15v? 3000 – 6t dt and solve this numerically using Euler's method in MATLAB with the initial condition v(0) = 0 and the step size h = 5 (include a screenshot), • plot a fully labelled graph of your results for 0 <t< 200 s, state the recursion relations (linking tn to tn-1 and vn to vn-1) you used to perform your numerical solution; and, state the maximum speed that the vehicle is able to reach in the interval 0 <t < 200 s. (B)
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