According to the statistics, among the students coming back from UK and USA, 1% are infected by COVID-19. They all take the saliva test with accuracy 99%. Suppose a particular student's saliva test is negative. A layman makes the following interpretation. The proba- bility that the student is infected in the first place is 0.01 (i.e., 1%). Since the test independently indicates that he is not infected and the error probability of the test is 0.01 (i.e., 1%), the actual probability of the student being infected is 0.01 × 0.01 = 0.01%. Comment on his interpretation.

According to the statistics, among the students coming back from UK and USA, 1% are infected by COVID-19. They all take the saliva test with accuracy 99%. Suppose a particular student's saliva test is negative. A layman makes the following interpretation. The proba- bility that the student is infected in the first place is 0.01 (i.e., 1%). Since the test independently indicates that he is not infected and the error probability of the test is 0.01 (i.e., 1%), the actual probability of the student being infected is 0.01 × 0.01 = 0.01%. Comment on his interpretation.

Name: According to the statistics, among the students coming back from UKan
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: According to the statistics, among the students coming back from UKand USA, 1% are infected by COVID-19. They all take the salivatest with accuracy 99%. Suppose a particular student's saliva test isnegative. A layman makes the following interpretati

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

the brand name of a certain chain of coffee shops has a 6% recognition rate in the town of Coffleton. An executive from the company wants to verify the recognition rate as the company is interested in opening a coffee shop in the town. he selects a random sample of 6 Coffleton residents, find the probabilty that the number that recognize the brand name is not 4
Based on information from a large insurance company, 66% of all damage liability claims are made by single people under the age of 25. A random sample of 54 claims showed that 41 were made by single people under the age of 25. Does this indicate that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company? State the null and alternate hypothesis. a) Ho: p = .66, Ha: p ≠ .66 b) Ho: p = .66, Ha: p > .66 c) Ho: p = .76, Ha: p < .76 d) Ho: p = .76, Ha: p > .76 e) Ho: p = .66, Ha: p < .66
in a study done in michigan, it was determined 38 (out of 62) poor children who attended pre-school needed social services later in life compared to 49 (out of 61) poor chidren who did not attend pre-schol. Does this stdy prevoide significant evidence that pre-school reudces the need for social services later in life
Could also you please show how to find Critial Values, Test Statisitc T, and the P value using a Calculator (TI 84) and whether it reject or fail to reject based on the evidence.
A peony plant with red petals was crossed with another plant having streaky petals. A nursery owner states that 75% of the offspring resulting from this cross will have red flowers. To test this claim, 100 seeds from this cross were collected and germinated, and 67 plants had red petals. What hypotheses should you use to test the nursery owner's claim? Ho: p = .75 vs. Ha: p * .75 Ho: p = .67 vs. Ha: p = .67 O Ho: p.75 vs. H₂: p= .75 Ho: p ≥.75 vs. Ha: p .75 O A 4. D W P
The Substance Abuse and Mental Health Services Administration (SAMHSA, 2017) estimates that 10.9% of the population of the United States age 18–24 had an episode of depression in the previous 12 months. Suppose a researcher takes a random sample of 225 United States adults aged 18–24. Determine the value of the sample proportion, p, such that 5% of samples of 225 United States adults age 18–24 are greater than p. You may find software or a z-table useful. Give your answer precise to three decimal places. p = II