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According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by Jkv? e-av? f,(v) = v > 0 elsewhere where a is a constant depending on its mass and the absolute temperature and k is 1 an appropriate constant. Show that the kinetic energy Y = - mv? is a random 2 variable having Gamma distribution.

According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by Jkv? e-av? f,(v) = v > 0 elsewhere where a is a constant depending on its mass and the absolute temperature and k is 1 an appropriate constant. Show that the kinetic energy Y = - mv? is a random 2 variable having Gamma distribution.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by kv² e-av² v > 0 f,(0) = elsewhere where a is a constant depending on its mass and the absolute temperature and k is an appropriate constant. Show that the kinetic energy Y = mV² is a random variable having Gamma distribution.
Transcribed Image Text:According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by kv² e-av² v > 0 f,(0) = elsewhere where a is a constant depending on its mass and the absolute temperature and k is an appropriate constant. Show that the kinetic energy Y = mV² is a random variable having Gamma distribution.
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