According to the ideal gas law, a 0.9307 mol sample of argon gas in a 1.952 L container at 267.4 K should exert a pressure of 10.46 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Ar gas, a = 1.345 L²atm/mol and b= 3.219x102 L/mol. %3D |Pideal - Pvan der Waals Percent difference х 100 Pideal+Pvan der Waals 0%

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According to the ideal gas law, a 0.9307 mol sample of argon gas in a 1.952 L container at 267.4 K should
exert a pressure of 10.46 atm. What is the percent difference between the pressure calculated using the van
der Waals' equation and the ideal pressure? For Ar gas, a =
1.345 L'atm/mol? and b= 3.219x10² L/mol.
|Pideal - Pvan der Waals
Percent difference
х 100
%3D
Pideal +Pvan der
Waals
%
Submit Answer
Transcribed Image Text:References Use the References to access important values if needed for this question. According to the ideal gas law, a 0.9307 mol sample of argon gas in a 1.952 L container at 267.4 K should exert a pressure of 10.46 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Ar gas, a = 1.345 L'atm/mol? and b= 3.219x10² L/mol. |Pideal - Pvan der Waals Percent difference х 100 %3D Pideal +Pvan der Waals % Submit Answer
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