According to the following reaction, how many milliliters, mL of 0.459 M HCI is needed to neutralize 12.04 grams of Ca(OH)2? Just give the numerical value. The assumption is the answer is in milliliters, mL. Reaction: 2 HCI(aq) + Ca(OH)2(aq) --> 2 H20(1) + CaCl2(aq)

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A: Given that: Volume of Ca(OH)2 = 350.0 mL Concentration of Ca(OH)2 = 0.450 M  Volume of HCl = 380.0…

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