According to the following combustion reaction, pure methanol liquid undergoes complete combustion with excess oxygen. If 55.79 liters, L of pure carbon dioxide, CO2 (water removed) was recovered at STP, how many milliliters, mL of methanol, CH3OH must have reacted? The density of liquid methanol is 0.792 g/mL. Just give the numerical value. The assumption is the answer is in milliliters, mL. Reaction: 2 CH3OH(I) + 3 O₂(g) --> 4 H₂O(g) + 2 CO₂(g)
According to the following combustion reaction, pure methanol liquid undergoes complete combustion with excess oxygen. If 55.79 liters, L of pure carbon dioxide, CO2 (water removed) was recovered at STP, how many milliliters, mL of methanol, CH3OH must have reacted? The density of liquid methanol is 0.792 g/mL. Just give the numerical value. The assumption is the answer is in milliliters, mL. Reaction: 2 CH3OH(I) + 3 O₂(g) --> 4 H₂O(g) + 2 CO₂(g)
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter7: Chemical Energy
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![According to the following combustion reaction, pure methanol
liquid undergoes complete combustion with excess oxygen. If 55.79
liters, L of pure carbon dioxide, CO2 (water removed) was recovered
at STP, how many milliliters, mL of methanol, CH3OH must have
reacted? The density of liquid methanol is 0.792 g/mL. Just give the
numerical value. The assumption is the answer is in milliliters, mL.
Reaction:
2 CH3OH(I) + 3 O₂(g) --> 4 H₂O(g) + 2 CO2(g)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe02f861e-172f-454f-ba05-ff7275092f44%2Fb372e863-825e-474e-8ed9-f4b4207218c0%2Fus322ba_processed.jpeg&w=3840&q=75)
Transcribed Image Text:According to the following combustion reaction, pure methanol
liquid undergoes complete combustion with excess oxygen. If 55.79
liters, L of pure carbon dioxide, CO2 (water removed) was recovered
at STP, how many milliliters, mL of methanol, CH3OH must have
reacted? The density of liquid methanol is 0.792 g/mL. Just give the
numerical value. The assumption is the answer is in milliliters, mL.
Reaction:
2 CH3OH(I) + 3 O₂(g) --> 4 H₂O(g) + 2 CO2(g)
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