According to the classical model of the Hydrogen atom, an electron moves in a circular orbit of radius r 3a in the xy-plane with constant velocity in the counter-clockwi se direction around the proton. Find the current produced due to the motion of the electron during its motion and the magnetic dipole moment in terms of unit vectors. a) I = i = (-R) év eva 2πα 2 b) I = i = eva(-k) %3D 4πα ji = ev (-R) ev c) I = бла d) I = i = 2eva(-k) %3D 8ла ev 5eva e) I = i %3D 10ла
According to the classical model of the Hydrogen atom, an electron moves in a circular orbit of radius r 3a in the xy-plane with constant velocity in the counter-clockwi se direction around the proton. Find the current produced due to the motion of the electron during its motion and the magnetic dipole moment in terms of unit vectors. a) I = i = (-R) év eva 2πα 2 b) I = i = eva(-k) %3D 4πα ji = ev (-R) ev c) I = бла d) I = i = 2eva(-k) %3D 8ла ev 5eva e) I = i %3D 10ла
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![of rad
11)
se
the el
According to the classical model of the Hydrogen atom, an electron moves in a
circular orbit of radius r= 3a in the xy-plane with constant velocity in the
counter-clockwise direction around the proton. Find the current produced due to
the motion of the electron during its motion and the magnetic dipole moment in
terms of unit vectors.
a) / =i= (-R)
ev
eva
2.
2na
2.
2ev
b) I
47ma
;i = eva(-k)
Sevo
3eva
c) =
6na
(-k)
d) =
i = 2eva(-k)
8ra
işare
krar
seva (-k)
e)/
10ma](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cad1424-51d5-48f1-899b-bbbae8c5df58%2Fbe077996-40a5-4821-abfe-ab84a4a5fd0c%2Fqyeogjs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:of rad
11)
se
the el
According to the classical model of the Hydrogen atom, an electron moves in a
circular orbit of radius r= 3a in the xy-plane with constant velocity in the
counter-clockwise direction around the proton. Find the current produced due to
the motion of the electron during its motion and the magnetic dipole moment in
terms of unit vectors.
a) / =i= (-R)
ev
eva
2.
2na
2.
2ev
b) I
47ma
;i = eva(-k)
Sevo
3eva
c) =
6na
(-k)
d) =
i = 2eva(-k)
8ra
işare
krar
seva (-k)
e)/
10ma
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