According to special relativity, a rod of length L moving at velocity v will shorten by an amount 8, given by: 8 = L(1- 1 where e is the speed of light (about 300 x 10° m/s). Consider a rod of 2 m long, and make three plots of 8 as a function of v for 0svs 300 x 10° m/s. In the first plot use linear scale for both axes. In the second plot use logarithmic scale for v and lincar scale for 8, and in the third plot use logarithmic scale for both v and 8."
According to special relativity, a rod of length L moving at velocity v will shorten by an amount 8, given by: 8 = L(1- 1 where e is the speed of light (about 300 x 10° m/s). Consider a rod of 2 m long, and make three plots of 8 as a function of v for 0svs 300 x 10° m/s. In the first plot use linear scale for both axes. In the second plot use logarithmic scale for v and lincar scale for 8, and in the third plot use logarithmic scale for both v and 8."
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Z 1 Mar 2021 at 18:04...
- According to special relativity, a rod of length L moving at velocity v will
shorten by an amount 8, given by:
- <(1-
8 =
where c is the speed of light (about 300 x 106 m/s). Consider a rod of 2 m
long, and make three plots of & as a function of v for 0svs 300 x 106 m/s. In
the first plot use linear scale for both axes. In the second plot use logarithmic
scale for v and linear scale for 8, and in the third plot use logarithmic scale for
both v and 8."
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