According to observer O, the ends of the rocket simultaneously line up with the ends of the platform. Are these events simultaneous to O`?
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- a) find velocit r ņ afder cullision. is moving to Hhe right mass m = with velou'ty v= 1"s and it collide s wi th at rest , all in one dimension. After He colli sion, velocity f m, is O.2' b) is th collisin elasdie or inelastic? K =! mvShow that the kinetic energy of a particle of mass m is related to the momentum p of that particleby, E =p^2/2m. (Hint: plug mv in for p and simplify!)A particle of mass m moves with a momentum of magnitude p. Express p in terms of KE.
- Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (ªHe) from gold-197 nuclei (197 Au). The energy of the incoming helium nucleus was 7.28 × 10-13 J, and the masses of the helium and gold nuclei were 6.68 × 10-27 kg and 3.29 × 10-25 kg, respectively (note that their mass ratio is 4 to 197). (Assume that the helium nucleus travels in the +x direction before the collision.) (a) If a helium nucleus scatters to an angle of 136° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 4He speed 197 Au velocity t 197 Au direction 14500000 0.0140 -17 m/s X m/s ° counterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus? 7.02e-13 JI need the answer as soon as possible13
- A car of mass 1500kg moving with a speed of 30.0 m/s collides and locks together with a 1200-kg car at rest at a stop sign. Show that momentum is conserved in a reference frame moving at 15.0 m/s in the direction of the moving car.The nonrelativistic expression for the momentum of a particle, p = mv, can be used if v « c. For what speed does the use of this formula give the following errors in the momentum? (а) 6.00% C (b) 11.0% CIm stuck on this one, keep loosing v in the cancels.
- If momentum is conserved in a collision where the mass has increased; what else must happen to meet the conservation law?If 2 marbles (of same mass and speed) travel from one end of a straight line runway and strike a line of marbles, is it possible to have only one marble to pop off the other end of the line at twice the speed? Why? (explain based on momentum and kinetic energy) I tried to find the momentum for the single marble and got 2mv and found the kinetic energy to be 2mv^2 but I'm not sure if it's right or how to how to explain it if it is possible or not.A particle of mass M, which was initially at rest, is hit by a particle of mass m, which is travelling at the speed Vi. The two particles collide and travel in different directions at the same pace Vf. Find the mass ratio M/m in terms of ß = vi/c, assuming a relativistic, elastic collision. Demonstrate that this reduces to Vi 0, the nonrelativistic meaning.