According to national data, 38% of US adults have blood type O-positive. Suppose that a random sample of 25 US adults is chosen. Use the Standard Deviation Rule and the properties of the sampling distribution of p-hat. There is a 68% chance that, in any random sample of 25 people, the proportion of people with blood type O-positive will be between: O .1373 and .6227 O .2829 and .4771 O .0888 and .6712
According to national data, 38% of US adults have blood type O-positive. Suppose that a random sample of 25 US adults is chosen. Use the Standard Deviation Rule and the properties of the sampling distribution of p-hat. There is a 68% chance that, in any random sample of 25 people, the proportion of people with blood type O-positive will be between: O .1373 and .6227 O .2829 and .4771 O .0888 and .6712
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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![According to national data, 38% of US adults have blood type O-positive. Suppose that a random
sample of 25 US adults is chosen.
Use the Standard Deviation Rule and the properties of the sampling distribution of p-hat. There is a 68%
chance that, in any random sample of 25 people, the proportion of people with blood type O-positive will
be between:
O .1373 and.6227
O .2829 and .4771
.0888 and .6712
O .3706 and .3894
O .1858 and .5742](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ad9afb9-8240-447b-bb0e-3ff183c8eb2d%2F2f851204-c1c6-4267-831d-b7880493f6d0%2Fn0n1ghe_processed.png&w=3840&q=75)
Transcribed Image Text:According to national data, 38% of US adults have blood type O-positive. Suppose that a random
sample of 25 US adults is chosen.
Use the Standard Deviation Rule and the properties of the sampling distribution of p-hat. There is a 68%
chance that, in any random sample of 25 people, the proportion of people with blood type O-positive will
be between:
O .1373 and.6227
O .2829 and .4771
.0888 and .6712
O .3706 and .3894
O .1858 and .5742
![A survey administered to a random sample of 625 U.S. college students found that 125 out of the
625 students surveyed were a member of a sorority or a fraternity.
Use the appropriate formula from the provided formula sheet.
Compute a 99% confidence interval for the proportion of U.S. college students who are a member of
a sorority or a fraternity. In the blank below, enter the upper bound of the 99% confidence interval for p.
For example, if your confidence interval is (0.115, 0.276), the upper bound would be 0.276. Provide your
answer as a decimal rounded to three decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ad9afb9-8240-447b-bb0e-3ff183c8eb2d%2F2f851204-c1c6-4267-831d-b7880493f6d0%2Fotilyk_processed.png&w=3840&q=75)
Transcribed Image Text:A survey administered to a random sample of 625 U.S. college students found that 125 out of the
625 students surveyed were a member of a sorority or a fraternity.
Use the appropriate formula from the provided formula sheet.
Compute a 99% confidence interval for the proportion of U.S. college students who are a member of
a sorority or a fraternity. In the blank below, enter the upper bound of the 99% confidence interval for p.
For example, if your confidence interval is (0.115, 0.276), the upper bound would be 0.276. Provide your
answer as a decimal rounded to three decimal places.
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