According to Mars, 24% of M&M plain candies are blue. In a given sample of 100 M&Ms, 27 are found to be blue. Assuming that the claimed rate of 24% is correct, find the probability of randomly selecting 100 M&Ms and getting 27 or more that are blue. Ans. 0.2791
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- When we test the hypothesis that the population proportions are equal, we can use the Z test for a one-sided as well as a two-sided alternative. Select one: a. False b. True C. Not sureMany college and university students obtain summer jobs. A professor wanted to determine whether students in different degree programs earn different amounts. She randomly selected five students in each of the 3 university programs and asked them to report what they earned the previous summer (in thousands of dollars). The following partially filled-in ANOVA table was obtained. Fill-in the rest of the table. (Use exact values for df and round all other numbers to 2 decimal places, if needed.) Source df MS F-Stat Treatments 12.4 Error Total 23.5In a survey of 500 drivers from the South, 408 wear a seat belt. In a survey of 370 drivers from the Northeast, 288 wear a seat belt. At a = 0.07, can you support the claim that the proportion of drivers who wear seat belts is greater in the South than in the Northeast? Assume the random samples are independent. Complete parts (a) through (e). (a) Identify the claim and state Ho and Ha The claim is "the proportion of drivers who wear seat belts in the South is greater than in the Northeast." Let p, represent the population proportion for the South, and p2 represent the population proportion for the Northeast. State Hg and H Choose the correct answer below. O B. Ho: P1 = P2 OC. Ho: P, * P2 O A. Ho: P1 > P2 H: P, SP2 H: P, *P2 Ha: P1 = P2 O D. Ho: P1 P2 OF. Ho: P1 2 P2 H,: P, OC. z
- Scenario: 200 people were asked, “Who is your favorite superhero?” Below are the data. Test the null hypothesis that the population frequencies for each category are equal. α= .05. Iron Man Black Panther Wonder Woman Spiderman fo = 40 fo = 60 fo =55 fo = 45 fe = fe = fe = fe = What is the correct result based on the data?A population has a mean of 50, and the standard deviation is 10. You take several samples and calculate sample means. 95% of these sample means lie between 46 and 54. What was the size of each sample? n= 1) 5 2) 4 3) 10 4) 2511. Add 6 to each number in the dataset. Then, the 15th percentile is:a. 1b. 6c. 8d. 7Use the following information to answer questions 12-14: Suppose the probability that an adult gets thenews from Facebook is 0.60. A random sample of 14 adults were surveyed to determine X, the numberof adults who get their news from Facebook.12. Which of the following statements is false?a. The set of possible x-values is {1, 2, 3, . . ., 14}b. X ~ B (14, 0.60)c. P(X=5) = 0.0408d. µ = 8.413. Find the probability that at least 6 adults get their news from Facebook.a. 0.8499b. 6/14c. 0.6429d. 0.941714. X is of data of type:a. categorical nominalb. categorical ordinalc. numerical continuousd. numerical discrete15. Suppose that the ages of Brunswick CC students are normally distributed. A random sample of 6Brunswick CC students reported the ages of 20, 35, 18, 45, 27, and 20 years old. Find the errorbound that corresponds to the 90% confidence interval for the true population mean age ofBrunswick CC…
- A researcher belleves that 52% of people who grew up as the only child have an IQ score over 100. However, unknown to the researcher, this figure is actually 50%, which is the same as in the general population. To attempt to find evidence for the claim, the researcher is going to take a random sample of 400 people who grew up as the only child. Let p be the proportion of people in the sample with an IQ score above 100. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p. (b) Find the standard deviation of p. (c) Compute an approximation for P(p 20.52), which is the probability that there will be 52% or more people with IQ Scores over 100 in the sample. Round your answer to four decimal places. 2022 acerA food company is planning to market a new kind of cereal; however before, they want to find the % of people who will like it. They select a random sample of 500 people and ask them to try the cereal. Of 500, 290 people say they like it. Compute the 95% cofidence interval for the % of the pop. that will like the cereal. Interept this cofidence interval.In one of the Stat 2 sections, the students in the section have an average height of 64 inches, with a standard deviation of 3 inches. The GSI happens to be 68 inches. Express the height of the GSI in standard units, relative to the students in the section. Choose the answer below that is closest. Group of answer choices 1.67 3.0 1.5 1.33 4.0 PreviousNext
- A sample is selected from a normal population with µ = 54 and σ = 8. Which of the following samples would be considered extreme and unrepresentative for this population? A. M = 53 and n = 81 B. M = 52 and n = 36 C. M = 53 and n = 36 D. M = 52 and n = 811.18 Cats on YouTube. Suppose you want to estimate the percentage of videos on YouTube that are cat videos. It is impossible for you to watch all videos on YouTube so you use a random video picker to select 1000 videos for you. You find that 2% of these videos are cat videos. Determine which of the following is an observation, a variable, a sample statistic (value calculated based on the observed sample), or a population parameterThe NIH is creating a test for the Zika virus. The incidence of a Zika is low, 11 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 0.03. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 0.1. Fill in the tree diagram and... Answer as a decimal to 4 decimal places. D = event that someone actually has Zika %3D positive = event that a test states that a person has Zika Conditional Marginal Probabilities Joint Probabilities Probabilities 0.9700 Enter an integer or decimal number [more..] P(D and positive) P(positive | D) False 0.1100 0.0300 negative P(D) P(negative | D) P(D and negative) 0.1000 False Positive 0.8900 P(no D) P(positive | no D) P(no D and positive) 0.9000 P(negative | no D) P(no D and negative)
