arginal pabilities Conditional Probabilities Joint Probabilities 0.9700 P(positive | D) Enter an integer or decimal number [ P(D and positive) False 1100 0.0300 negative P(D) P(negative | D) P(D and negative) .8900 0.1000 False Positive itvolno D) P/no D and positive)
arginal pabilities Conditional Probabilities Joint Probabilities 0.9700 P(positive | D) Enter an integer or decimal number [ P(D and positive) False 1100 0.0300 negative P(D) P(negative | D) P(D and negative) .8900 0.1000 False Positive itvolno D) P/no D and positive)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 11 percent in the general
population. There is a trial version, but it sometimes misses the disease. The probability of a false
negative is 0.03. Similarly, someone who does not have Zika, will sometimes get a positive reading. The
probability of this is 0.1. Fill in the tree diagram and...
Answer as a decimal to 4 decimal places.
D = event that someone actually has Zika
%3D
positive = event that a test states that a person has Zika
Conditional
Marginal
Probabilities
Joint Probabilities
Probabilities
0.9700
Enter an integer or decimal number [more..]
P(D and positive)
P(positive | D)
False
0.1100
0.0300
negative
P(D)
P(negative | D)
P(D and negative)
0.1000
False Positive
0.8900
P(no D)
P(positive | no D)
P(no D and positive)
0.9000
P(negative | no D)
P(no D and negative)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d14b178-5b8c-4639-9880-9a6310b5f0da%2Fe08b5b48-4682-4cb9-9c49-dee178d4c447%2Fpahnahk_processed.png&w=3840&q=75)
Transcribed Image Text:The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 11 percent in the general
population. There is a trial version, but it sometimes misses the disease. The probability of a false
negative is 0.03. Similarly, someone who does not have Zika, will sometimes get a positive reading. The
probability of this is 0.1. Fill in the tree diagram and...
Answer as a decimal to 4 decimal places.
D = event that someone actually has Zika
%3D
positive = event that a test states that a person has Zika
Conditional
Marginal
Probabilities
Joint Probabilities
Probabilities
0.9700
Enter an integer or decimal number [more..]
P(D and positive)
P(positive | D)
False
0.1100
0.0300
negative
P(D)
P(negative | D)
P(D and negative)
0.1000
False Positive
0.8900
P(no D)
P(positive | no D)
P(no D and positive)
0.9000
P(negative | no D)
P(no D and negative)
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