According to Keynote Systems, Wal-Mart's website was available 95% of the time during themost recent holiday shopping season. Assuming this finding to be based on a random sample of200 attempts, the 98% confidence interval for the population proportion of the time the Wal-Mart site was available during this period is0.9246 to 0.97540.9141 to 0.98590.9278 to 0.97220.9303 to 0.96970.9198 to 0.98023♫JMAWP

Answered: Image /qna-images/answer/e57e808e-fc53-4283-ba50-cecbc74bd269.jpg

Answered: According to Keynote Systems,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Out of a 54 person sample from our fall Math-150 classes, 12.4% of the students are left-handed. Using a TI 84 graphing calculator: Construct an 80% confidence interval for the population proportion, p. Round to tenths of a percentand write a sentence answer.The U.S. has 13.1% of it’s population that are left-handed. Did this fall in your confidence interval from part a? Be sure to show all calculator commans used.
If n=15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
A survey was conducted to determine what percentage of college seniors would have chosen to attend a differentcollege if they had known then what they know now. In a random sample of 100 seniors, 34 percent indicated thatthey would have attended a different college. A 90 percent confidence interval for the percentage of all seniors whowould have attended a different college is
if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
In a survey funded by the UW school of medicine, 750 of 1000 adult Seattle residents said they did not believe they could come down with a sexually transmitted infection (STI). Construct a 95% confidence interval estimage of the proportion of adult Seattle residents who don't believe they can contract an STI. (Use a z score of 1.96 for your computations.) (.728, .772) (.723, .777) (.718, .782) (.713, .878) (.665, .835)
In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that 160 preferred seafood. A 99% confidence interval for the actual proportion of people eating seafood on Fridays (rounded off to two decimals) is: A. [0.28; 0.36] B. [0.29; 0.35] C. [0.27; 0.37] D. [0.26; 0.36]
create a 90% confidence interval for the following data: x = 25 n = 100
A telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the South and the Northeast. The representative's belief is based on the results of a survey. The survey included a random sample of 700700 southern residents and 580580 northeastern residents. 49%49% of the southern residents and 42%42% of the northeastern residents reported that they were completely satisfied with their local telephone service. Find the 80%80% confidence interval for the difference in two proportions. Step 2 of 3: Find the value of the standard error. Round your answer to three decimal places.
Suppose NBC has asked the same question to a sample of 1296 adults nine months earlier, finding 47% with an optimistic outlook for the year ahead. Develop a 95% confidence interval for the percentage of American adults who had an optimistic outlook for the economy nine months earlier.
An insurance company collects data on seat-belt use among drivers in a country. Of 1500 drivers 30-39 years old, 33% said that they buckle up, whereas 458 of 1800 drivers 55-64 years old said that they did. Find a 95% confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups 30-39 years and 55-64 years. ..... Construct a 95% confidence interval. The 95% confidence interval for p, - p2 is from to (Round to three decimal places as needed.)
In a sample of 100 college students, 25 of them own a car. Calculate the 95% confidence interval for the true population of college students who own a car. Choose the closest one. A. (0.165132, 0.334868) B. (0.231725, 0.452302) C. (0.25, 0.75) D. (0.1, 0.9)

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