According to dimensions and the loading conditions given in the figure above, calculate the maximum bending stress due to the bending moment. 31511 21512
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A: Draw shear force and bending moment diagram and also find the maximum bending stress.
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- Q8\ sketch the axial load, shear force and bending moment diagrams. 12 kN 16 kN/m 12 kN 16 kN B 6 kN/m HD VA 5.0 m 3.0 m VD 8.0 m 4.0 mDownloads/ * Practice problem 2 Determine the location of the shear centre O of the thin-walled member of uniform thickness having the cross-section shown. [Ans. 5a/7] UNIVERSITY OF LIVERPOOL $ 4 € R LL F % 5 T G 40 6 Y & O. 7 T Second moment of area liyi U E H J 2a 8 S B K O O L P [ = www.check-p www.check-plag This site was upc via Microsoft Edge delete backspace #strength of material MENG222 Please solve the problem step by step and make your line clear and don't forget FBD and show me your step Please make sure your answer is correct please p1=123 p2=12
- Figure 1 shows a composite shaft ABCD acted upon horizontal forces. The moduli of elasticity and the cross-section areas of the segments of the shaft are also provided. Eal = 70 GPa AAB = 58 mm? Ecu = 126 GPa Est 200 GPa %3D %3D Авс 3D 77 mm? AcD = 39 mm2 АВ Сopper 20kN 8 kN Aluminum Steel 7 kN A B 20kN 8 kN 450 mm -300 mm- 400 mm Figure 1: Axially loaded composite shaft 2.1. Construct the diagram of internal normal forces for each cross-section of the shaft 2.2. Calculate the displacement of the point C with respect to the fixed-point A. 2.3. If the shaft must have one uniform diameter, determine the required minimum diameter of the shaft if the normal yield stress in the composite shaft must not exceed 450 MPa with a factor of safety equal to 1.8.Two solid circular shafts are connected through a flange bolt coupling consisting of 3 circular bolt rows. The free ends of the shafts are to be subjected by equal torque. Solid Shafts Diameter (mm) Length (m) Shear Modulus (GPa) Shaft A Shaft B 65 66 3 3.8 81 84.6 Flange-bolt coupling Bolt Circle Diameter (mm) Bolt Alowable Shear Stress (MPa) Bolt Diameter Shear Modulus Number of Bolt Row (mm) (GPa) Bolts 1 95 14 77 35 4 2 116 17 97 42 10 3 135 13 93 49 14 A Calculate the torque capacity of the flange-bolt coupling (kN-m). B. Calculate the stresses in both shaft if the torque capacity is applied at both ends (MPa). C. Calculate the total angle of twist (in degrees).9-22. Solve Prob. 9-21 using Castigliano's theorem. Internal Moment Function M(x): The internal moment function in terms of the load P' and couple moment M' and externally applied load are shown on figures (a) and (b), respectively. Castigliano's Second Theorem: The displacement at C can be determined aM(x) ap' aM dx [M(M) +/G-04] ↓ with PL³ 48E1 To determine the slope at B, with setting M = 0. and set P = P. EI PL² 16EI OM dx OM EL ~ ) ) » (¹-2) & aM(x₂) X₁ M(x₂) aM' LaM Ans. and Ans. 12 M MOC+ PMOC-M²+(£- #%₂ Ti *44 6 244 aft 214
- Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M = 13 kN-m Ay = 3.46 KN Dy Units: KN = 32.54 kN M 4 m 29.5 kN-m 43.3 kN-m 25.8 kN-m O 22.9 kN-m 31.48 kN-m B Ay 4 m 15 kN C Ay 4 m Ay-15 7 kN/m D 3 m 21 Ay-15 E Xう shear Frce 0くx八 5 kM 二 Ci) 5-10 = -5 kN 65x510 X s lo Sミ 5-lo ニ -5kN S = -5KN Bending moment M. = 5x) ニ 5x-10(n-4) ニ ー5x+40 6Determine the values of shear force and bending moment for the bar in the image as a function of the x coordinate. Qmin=?Qmax=?Mmax=? benging moments max as x coordinate x= q=18 nN/m F=13 kN M=6 kNm L1=1.1m L2= 1.7m L3=1.4m L4= 1.7 mThe cantilever beam is supported by a fixed support at A, and subjected to the force F = 550 lb and the couple M = 2870 ft-lb. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take x = 0 at point A. c 03O 2013 Michael Swanbom F CC BY NC SA M A • B a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 6.2 ft 4.34 ft Support Reactions The force reaction at A is lb (take up as positive). The couple moment reaction at A is lb (take counterclockwise as positive). Shear Force and Bending Moment Equations In section AB: V(x)= lb and 'M(x)= ft-lb. In section BC: V(x)= lb and 'M(x)= ft-lb.The permissible bending stress of a gear material is 150 MPa with a radial load of 100N acting upon it. What is the magnitude of the resultant load acting on the tooth for the given dimensions? 20 30 All dimensions are in mm 8.W 8 L/2 1/2 WzSEE MORE QUESTIONS