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According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the frustum of a cone depicted in the figure below. use bisection to determine the height, h, of the portion that is above water. Employ the following values for your computation: = 0.5 m. r2 = 1 m, h=1 m. pf=frustum density = 100 kg/m³, and Pw = water density = 1000 kg/m³. (Round the final answer to four decimal places.) Note that the volume of a frustum is given by V= (+r+r₂) h 12

According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the frustum of a cone depicted in the figure below. use bisection to determine the height, h, of the portion that is above water. Employ the following values for your computation: = 0.5 m. r2 = 1 m, h=1 m. pf=frustum density = 100 kg/m³, and Pw = water density = 1000 kg/m³. (Round the final answer to four decimal places.) Note that the volume of a frustum is given by V= (+r+r₂) h 12

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According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the frustum of a cone depicted in the figure below, use bisection to determine the height, h, of the portion that is above water. Employ the following values for your computation: = 0.5 m. r2 = 1 m, h=1 m. pf=frustum density = 100 kg/m³, and Pw=water density = 1000 kg/m³. (Round the final answer to four decimal places.) Note that the volume of a frustum is given by V=(r+r+rir₂) h 12 The height of the portion that is above water hy is 0.667 m.
Transcribed Image Text:According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the frustum of a cone depicted in the figure below, use bisection to determine the height, h, of the portion that is above water. Employ the following values for your computation: = 0.5 m. r2 = 1 m, h=1 m. pf=frustum density = 100 kg/m³, and Pw=water density = 1000 kg/m³. (Round the final answer to four decimal places.) Note that the volume of a frustum is given by V=(r+r+rir₂) h 12 The height of the portion that is above water hy is 0.667 m.
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