According to an estimate, the average total parent and student debt for new college graduates was $34,400 in 2010-11 (Time, October 31, 2011). A random sample of 490 of this year's graduates showed that their average such debt is $37,000 with a standard deviation of $5470. Do the data provide significant evidence at a 1% significance level to conclude that the current average total parent and student debt for new graduates is higher than $34,400? Use both the p-value approach and the critical-value approach. Use the p-value approach. Use the t distribution table to find a range for the p-value. Enter the exact values for the range. 0.0000 < p-value < 0.001 Use the critical-value approach. Round your observed value to four decimal places, and your critical value to two decimal places. Observed value = %3D

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Please answer each step in this question. Idk how to get the observed t. If whoever answer this question go through each step specifically it will be gladly appreciated. 

i posted this other question along with as well as i dont think i should use another question ask for a short problem

4:19 1
M4A6 Chapter 09 Practice
+ M4A6 Chapter 09 Practice
9 of 13
>
0.8 / 1
According to an estimate, the average total parent
and student debt for new college graduates was
$34,400 in 2010-11 (Time, October 31, 2011). A
random sample of 490 of this year's graduates
showed that their average such debt is $37,000
with a standard deviation of $5470. Do the data
provide significant evidence at a 1% significance
level to conclude that the current average total
parent and student debt for new graduates is
higher than $34,400? Use both the p-value
approach and the critical-value approach.
Use the p-value approach. Use the t distribution
table to find a range for the p-value. Enter the
exact values for the range.
0.0000
< p-value <
0.001
Use the critical-value approach. Round your
observed value to four decimal places, and your
critical value to two decimal places.
Observed value =
Transcribed Image Text:4:19 1 M4A6 Chapter 09 Practice + M4A6 Chapter 09 Practice 9 of 13 > 0.8 / 1 According to an estimate, the average total parent and student debt for new college graduates was $34,400 in 2010-11 (Time, October 31, 2011). A random sample of 490 of this year's graduates showed that their average such debt is $37,000 with a standard deviation of $5470. Do the data provide significant evidence at a 1% significance level to conclude that the current average total parent and student debt for new graduates is higher than $34,400? Use both the p-value approach and the critical-value approach. Use the p-value approach. Use the t distribution table to find a range for the p-value. Enter the exact values for the range. 0.0000 < p-value < 0.001 Use the critical-value approach. Round your observed value to four decimal places, and your critical value to two decimal places. Observed value =
For the following significance level, what is the
probability of making a Type l error?
a = 0.02
i
!
Transcribed Image Text:For the following significance level, what is the probability of making a Type l error? a = 0.02 i !
Expert Solution
Step 1

Given information-

Population mean, μ = $34,400

Sample size, n = 490

Sample mean, x = $37,000

Sample standard deviation, s = $5470

Significance level, α = 0.01

For this study we will use right tailed t-test statistics.

Hypothesis Formulation-

Null Hypothesis, H0: μ = $34,400

Alternate Hypothesis, Ha: μ > $34,400

Since here population standard deviation is unknown so using t-test statistics.

Step 2

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