According to ACI code min allowed diameter of circular column is450mm450cm300cm300mm* In design of slab shear if Vu more than ØVc thenincrease slab thicknessuse strirrupsdecrease slab thicknessuse additional longitudinal reinforcement

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Answered: According to ACI code min allowed…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Subject is Reinforced Concrete Design
Discuss the suitability of different types of column supported by RC slab.
4.7 The cross section of a conventionally reinforced concrete one-way slab is shown below. Using ACI Table 9.5(a), answer the following questions: 5'-0" CANTILEVER TI 23-0 END-BAY T2 SPAN L3 INTERIOR-BAY a. What is the minimum slab thickness at end bays (T2)? Member Solid one- way slabs BM WIDTH Beams or ribbed one- way slabs TABLE 9.5(a)- - MINIMUM THICKNESS OF NONPRESTRESSED BEAMS OR ONE-WAY SLABS UNLESS DEFLECTIONS ARE CALCULATED Simply supported 23-0 END-BAY 12 €/16 CANTILEVER Minimum thickness, h Both ends One end continuous continuous Cantilever Members not supporting or attached to partitions or other construction likely to be damaged by large deflections 1/20 024 U/28 U/10 d/18.5 (21 €/8 Notes: Values given shall be used directly for members with normalweight concrete and Grade 60 reinforcement. For other conditions, the values shall be modified as follows: a) For lightweight concrete having equilibrium dersity, we, in the range of 90 to 115 loft, the values shall be multiplied…
3 4 5 the limiting diameter thickness ratio "D/t" of hollow circular section in flexure for compact section is_ a. 0.070*E/Fy b. 0.11*E/Fy c. 0.270*E/Fy d. NOTA the limiting diameter thickness ratio "D/t" of hollow circular section in flexure for non compact section is a. 0.070*E/Fy b. 0.11*E/Fy c. 0.31*E/Fy d. NOTA the limiting diameter thickness ratio "D/t" of hollow circular section in compresion for compact section is a. 0.070*E/Fy b. 0.11*E/Fy c. 0.31*E/Fy d. NOTA
Problem # 2 The slab shown is unsupported along the longer edge and fixed all the other sides. It sustains a service live load if 5 kPa, and sustains the slab weight as service dead load (concrete density if 23.56 kN/m³). Assuming fc'=28 MPa, fy =415 MPa and slab thickness of 165 mm, determine design moments using the strip method. 3.6 m 5.7 m
A simply supported 1 way slab having span of 3 meters is to carry the load for DL = 5kpa and LL = 4.8Kpa. If the concrete f'c = 28Mpa and rebar to be used is 10mm with fy = 276Mpa. a.) Determine the minimum thickness of the 1 way slab.(answer in millimeter in whole number) b.) Determine the Ultimate loading combination for the slab considering 1 meter strip?(answer in KN/m. in 3 decimal places ) c.) Determine the Ultimate moment for the slab considering 1 meter strip?(answer in KN-m. in 3 decimal places) d.) Determine the effective depth of the slab considering concrete cover = 20mmanswer in millimeter. in whole number e.) Determine the area of reinforcement for the slab based on the actual loadings.(answer in sq.mm. in 3 decimal places) f.) Determine the spacing of the rebar.(answer in millimeter(Don't round up, use actual value). in 3 decimal places)
H.W.1: One-Way Slab: 1. Check slab thíckness. 2.Check shear force. 3.Design flexural reinforcement for the slab. I 4.Dosign flexural roinforcement for continuous beam B. fe=28Mpa 6m 5.8m 5.8m 6m f,-420Mpa Slab h=250mm 6m Beam Section: ha600mm bw#350mm Column Section: 500x500mm 7m LL=5kN/m? Exterior D.L-4kN/m? 7m K
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The following diagram shows a partial floor framing plan of an elevated walkway building connecting an airport terminal building to the adjacent garage. The concrete floor is not post- tensioned. Material properties are: - Concrete weight: wt = 150 pcf - Concrete compressive strength: f'c = 4000 psi - Steel tensile strength: fy = 60 ksi - Stirrup consists of #4 bar - Framing members are not exposed to weather or in contact with soil. Per the ACI, what is the minimum slab depth? Consider both the interior slab and the cantilevered slab at the edge of the building. 30-0¹ B4 B4 B4 83 Column 52 SI 30-0 -Sab Mark Dean- B4 B4 B4 83 B 30-0¹ BI B2 B2 BI -Girder 12 A 1 3-4 Ei 13:4 05 40-0 to 2
3) As per NSCP 2015, a minimum shear reinforcement in concrete design shall be provided in all regions where Vu > 0.5φVc except for the following cases: A. member has shallow depth of less than 150 mm (ex. slabs) or integral with slab with depth greater of 2.5tf or 0.5bw and 600 mm B. member has shallow depth of less than 200 mm (ex. slabs) or integral with slab with depth greater of 2.5tf or 0.5bw and 600 mm C. member has shallow depth of less than 250 mm (ex. slabs) or integral with slab with depth greater of 2.5tf or 0.5bw and 600 mm D. member has shallow depth of less than 300 mm (ex. slabs) or integral with slab with depth greater of 2.5tf or 0.5bw and 600 mm
Reinforced Concrete

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According to ACI code min allowed diameter of circular column is 450mm 450cm 300cm 300mm In design of slab shear if Vu more than ØVc then increase slab thickness use strirrups decrease slab thickness use additional longitudinal reinforcement