According to a Wakefield Research survey of adult women, 50% of the women said that they had tried five or more diets in their lifetime (USA TODAY, June 21, 2011). Suppose that this result is true for the current population of adult women. A random sample of 9 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in this sample of 9 who had tried five or more diets in their lifetime is a. at most 7 Round your answer to four decimal places. P( at most 7) = i b. 1 to 3 Round your answer to four decimal places.

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### Probability Exercise: Binomial Distribution

According to a Wakefield Research survey of adult women, 50% of the women stated that they had tried five or more diets in their lifetime (USA TODAY, June 21, 2011). Suppose this result is true for the current population of adult women. A random sample of 9 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in this sample of 9 who had tried five or more diets in their lifetime is:

#### a. At most 7
- **Task**: Calculate \( P(\text{at most } 7) \) 
- **Instruction**: Round your answer to four decimal places.

\[ P(\text{at most } 7) = \quad \text{[Input Box]} \]

---

#### b. Between 1 and 3
- **Task**: Calculate \( P(1 \text{ to } 3) \) 
- **Instruction**: Round your answer to four decimal places.

\[ P(1 \text{ to } 3) = \quad \text{[Input Box]} \]

---

#### c. At least 7
- **Task**: Calculate \( P(\text{at least } 7) \) 
- **Instruction**: Round your answer to four decimal places.

\[ P(\text{at least } 7) = \quad \text{[Input Box]} \] 

### Explanation

For each scenario, apply the principles of the binomial distribution, where the number of trials is 9, and the probability of success on each trial (a woman having tried five or more diets) is 0.5. Use statistical tools or binomial tables to aid in calculation. Remember to interpret probability as the likelihood of a specific number of successes in a set number of trials.
Transcribed Image Text:### Probability Exercise: Binomial Distribution According to a Wakefield Research survey of adult women, 50% of the women stated that they had tried five or more diets in their lifetime (USA TODAY, June 21, 2011). Suppose this result is true for the current population of adult women. A random sample of 9 adult women is selected. Use the binomial probabilities table or technology to find the probability that the number of women in this sample of 9 who had tried five or more diets in their lifetime is: #### a. At most 7 - **Task**: Calculate \( P(\text{at most } 7) \) - **Instruction**: Round your answer to four decimal places. \[ P(\text{at most } 7) = \quad \text{[Input Box]} \] --- #### b. Between 1 and 3 - **Task**: Calculate \( P(1 \text{ to } 3) \) - **Instruction**: Round your answer to four decimal places. \[ P(1 \text{ to } 3) = \quad \text{[Input Box]} \] --- #### c. At least 7 - **Task**: Calculate \( P(\text{at least } 7) \) - **Instruction**: Round your answer to four decimal places. \[ P(\text{at least } 7) = \quad \text{[Input Box]} \] ### Explanation For each scenario, apply the principles of the binomial distribution, where the number of trials is 9, and the probability of success on each trial (a woman having tried five or more diets) is 0.5. Use statistical tools or binomial tables to aid in calculation. Remember to interpret probability as the likelihood of a specific number of successes in a set number of trials.
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