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Suppose a basketball player makes 57.7% of shots and that the probabilty of making each shot is independent. If the basketball player attempts 3 shots, what is the probability of making at least one shot? Enter your answer rounded to at least 4 decimals.

Suppose a basketball player makes 57.7% of shots and that the probabilty of making each shot is independent. If the basketball player attempts 3 shots, what is the probability of making at least one shot? Enter your answer rounded to at least 4 decimals.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Problem Text:** Suppose a basketball player makes 57.7% of shots and that the probability of making each shot is independent. If the basketball player attempts 3 shots, what is the probability of making at least one shot? Enter your answer rounded to at least 4 decimals. **Solution Explanation:** To find the probability of making at least one shot, we can use the complementary probability. First, calculate the probability of not making a shot, which is \(1 - 0.577 = 0.423\). Next, find the probability of missing all 3 shots: \(0.423^3 = 0.0757\) (rounded to four decimals). The probability of making at least one shot is the complement of missing all shots, calculated as follows: \(1 - 0.0757 = 0.9243\). Thus, the probability of making at least one shot is **0.9243**.
Transcribed Image Text:**Problem Text:** Suppose a basketball player makes 57.7% of shots and that the probability of making each shot is independent. If the basketball player attempts 3 shots, what is the probability of making at least one shot? Enter your answer rounded to at least 4 decimals. **Solution Explanation:** To find the probability of making at least one shot, we can use the complementary probability. First, calculate the probability of not making a shot, which is \(1 - 0.577 = 0.423\). Next, find the probability of missing all 3 shots: \(0.423^3 = 0.0757\) (rounded to four decimals). The probability of making at least one shot is the complement of missing all shots, calculated as follows: \(1 - 0.0757 = 0.9243\). Thus, the probability of making at least one shot is **0.9243**.
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