According to a survey in a country, 31% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1- p) < 10 O B. Approximately normal because ns 0.05N and np(1- p) 2 10 O C. Approximately normal because ns 0.05N and np(1- p) < 10 O D. Not normal because ns0.05N and np(1 – p) 2 10 Determine the mean of the sampling distribution of p. | (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. on = (Round to three decimal places as needed.)

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According to a survey in a country, 31% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Complete parts (a)
through (d) below.
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the
sampling distribution of p below.
O A. Not normal because ns0.05N and np(1 - p) < 10
O B. Approximately normal because ns0.05N and np(1 - p) 2 10
OC. Approximately normal because ns0.05N and np(1 - p) < 10
O D. Not normal because ns0.05N and np(1 - p) 2 10
Determine the mean of the sampling distribution of p.
|(Round to two decimal places as needed.)
Ha
Determine the standard deviation of the sampling distribution of p.
(Round to three decimal places as needed.)
Transcribed Image Text:According to a survey in a country, 31% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1 - p) < 10 O B. Approximately normal because ns0.05N and np(1 - p) 2 10 OC. Approximately normal because ns0.05N and np(1 - p) < 10 O D. Not normal because ns0.05N and np(1 - p) 2 10 Determine the mean of the sampling distribution of p. |(Round to two decimal places as needed.) Ha Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.)
(b) What is the probability that in a random sample of 400 adults, more than 35% do not own a credit card?
The probability is |
(Round to four decimal places as needed.)
Interpret this probability.
| to result in more than 35% not owning a credit card.
If 100 different random samples of 400 adults were obtained, one would expect
(Round to the nearest integer as needed.)
(c) What is the probability that in a random sample of 400 adults, between 30% and 35% do not own a credit card?
The probability is
(Round to four decimal places as needed.)
Interpret this probability.
If 100 different random samples of 400 adults were obtained, one would expect
to result in between 30% and 35% not owning a credit card.
(Round to the nearest integer as needed.)
Transcribed Image Text:(b) What is the probability that in a random sample of 400 adults, more than 35% do not own a credit card? The probability is | (Round to four decimal places as needed.) Interpret this probability. | to result in more than 35% not owning a credit card. If 100 different random samples of 400 adults were obtained, one would expect (Round to the nearest integer as needed.) (c) What is the probability that in a random sample of 400 adults, between 30% and 35% do not own a credit card? The probability is (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 400 adults were obtained, one would expect to result in between 30% and 35% not owning a credit card. (Round to the nearest integer as needed.)
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