According to a proctor test carried out on a soil, the following results were obtained. Draw thecorresponding curve on millimeter paper, obtain the optimum humidity and the corresponding maximumdry volumetric weight, and plot the line of zero voids or theoretical saturation. Consider a Gs = 2.81.wwww wwwProctor's Results:SampleWt of soil +mold (g)Wt of mold(g)Soil Wt (g)12.46061.56106.56122.561064354435443544354Vol. Of mold(m3)Spec WeightWet (kg /0.000942 0.000942 0.000942 0.000942m3) Moisture contentSieve NoК-9K-5K-11K-23K-19K-28K-10K5w1 (wet soil+ Sieve) (g)w2(dry soil +Sieve) (g)157160179169.5163.5153.5154.5178132129144.5137.5130.5124.3124140Wt of the31.931.231.631.131.231.431.531sieve (g)w%W%Spec WeightDry (kg / m3)Additionally, according to the field test carried out (ASTM D-1556), it is desired to obtain the followingvalues: Wet Specific Weight ywet., Dry Specific Weight yd and% Compaction.DataOttawa Sand Density = 95.57 Ib / ft3 Mass of sand in cone = 3.86 IbBottle or Container: Mass before use sand + cone + container = 16,121 Ib Mass after use =4,894 b.Soil weight in hole, Ws = 8,327 lb Soil Moisture Content, w =:

The given values are as folowsThe ottawa sand density=95.57lb/ft3Mass of the sand in cone…

According to a proctor test carried out on a soil, the following results were obtained. Draw the corresponding curve on millimeter paper, obtain the optimum humidity and the corresponding maximum dry volumetric weight, and plot the line of zero voids or theoretical saturation. Consider a Gs = 2.81. Proctor's Results: Sample 1 2 3 4 Wt of soil + 6061.5 6106.5 6122.5 6106 mold (g) Wt of mold (g) Soil Wt (g) Vol. Of mold |(m3) Spec Weight Wet (kg / 4354 4354 4354 4354 0.000942 0.000942 0.000942 0.000942

According to a proctor test carried out on a soil, the following results were obtained. Draw the corresponding curve on millimeter paper, obtain the optimum humidity and the corresponding maximum dry volumetric weight, and plot the line of zero voids or theoretical saturation. Consider a Gs = 2.81. Proctor's Results: Sample 1 2 3 4 Wt of soil + 6061.5 6106.5 6122.5 6106 mold (g) Wt of mold (g) Soil Wt (g) Vol. Of mold |(m3) Spec Weight Wet (kg / 4354 4354 4354 4354 0.000942 0.000942 0.000942 0.000942

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

According to a proctor test carried out on a soil, the following results were obtained. Draw the
corresponding curve on millimeter paper, obtain the optimum humidity and the corresponding maximum
dry volumetric weight, and plot the line of zero voids or theoretical saturation. Consider a Gs = 2.81.
wwww www
Proctor's Results:
Sample
Wt of soil +
mold (g)
Wt of mold
(g)
Soil Wt (g)
1
2.
4
6061.5
6106.5
6122.5
6106
4354
4354
4354
4354
Vol. Of mold
(m3)
Spec Weight
Wet (kg /
0.000942 0.000942 0.000942 0.000942
m3)

Moisture content
Sieve No
К-9
K-5
K-11
K-23
K-19
K-28
K-10
K5
w1 (wet soil
+ Sieve) (g)
w2(dry soil +
Sieve) (g)
157
160
179
169.5
163.5
153.5
154.5
178
132
129
144.5
137.5
130.5
124.3
124
140
Wt of the
31.9
31.2
31.6
31.1
31.2
31.4
31.5
31
sieve (g)
w%
W%
Spec Weight
Dry (kg / m3)
Additionally, according to the field test carried out (ASTM D-1556), it is desired to obtain the following
values: Wet Specific Weight ywet., Dry Specific Weight yd and% Compaction.
Data
Ottawa Sand Density = 95.57 Ib / ft3 Mass of sand in cone = 3.86 Ib
Bottle or Container: Mass before use sand + cone + container = 16,121 Ib Mass after use =
4,894 b.
Soil weight in hole, Ws = 8,327 lb Soil Moisture Content, w =:

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Question attached
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