According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.158. The probability that a randomly selected person has vision problems is 0.084. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. C. Yes, because this is an application of the Addition Rule for Disjoint Events. D. No, because hearing problems and vision problems are events that are too similar to one another.

According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.158. The probability that a randomly selected person has vision problems is 0.084. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. C. Yes, because this is an application of the Addition Rule for Disjoint Events. D. No, because hearing problems and vision problems are events that are too similar to one another.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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