Please help with the probability of a child having a blue eye color. I'm not sure if I have it right
Addition Rule of Probability
It simply refers to the likelihood of an event taking place whenever the occurrence of an event is uncertain. The probability of a single event can be calculated by dividing the number of successful trials of that event by the total number of trials.
Expected Value
When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known as the expectation, is denoted by: E(X).
Probability Distributions
Understanding probability is necessary to know the probability distributions. In statistics, probability is how the uncertainty of an event is measured. This event can be anything. The most common examples include tossing a coin, rolling a die, or choosing a card. Each of these events has multiple possibilities. Every such possibility is measured with the help of probability. To be more precise, the probability is used for calculating the occurrence of events that may or may not happen. Probability does not give sure results. Unless the probability of any event is 1, the different outcomes may or may not happen in real life, regardless of how less or how more their probability is.
Basic Probability
The simple definition of probability it is a chance of the occurrence of an event. It is defined in numerical form and the probability value is between 0 to 1. The probability value 0 indicates that there is no chance of that event occurring and the probability value 1 indicates that the event will occur. Sum of the probability value must be 1. The probability value is never a negative number. If it happens, then recheck the calculation.
![**Topic: Genotype and Eye Color Probability**
**Genotype Example: Blue/Brown Eyes**
Each of two parents has the genotype blue/brown, which consists of the pair of alleles that determine eye color, and each parent contributes one of those alleles to a child. Assume that if the child has at least one blue allele, that color will dominate and the child's eye color will be blue.
**Possible Outcomes:**
a. List the different possible outcomes. Assume that these outcomes are equally likely. (Round to two decimal places as needed.)
**Solution:**
The possible combinations of alleles the child can inherit are:
1. Blue from the first parent and blue from the second parent (B/B).
2. Blue from the first parent and brown from the second parent (B/b).
3. Brown from the first parent and blue from the second parent (b/B).
4. Brown from the first parent and brown from the second parent (b/b).
Since blue is the dominant allele, any combination that includes at least one blue allele (B) will result in blue eyes.
**Probability Calculation:**
c. The probability that the child will have blue eye color is \(0.75\) (Round to two decimal places as needed).
**Detailed Calculation:**
- Probability of B/B (blue/blue) = 1/4 = 0.25
- Probability of B/b (blue/brown) = 1/4 = 0.25
- Probability of b/B (brown/blue) = 1/4 = 0.25
- Probability of b/b (brown/brown) = 1/4 = 0.25
Adding the probabilities of outcomes resulting in blue eyes (B/B, B/b, b/B):
\[ 0.25 + 0.25 + 0.25 = 0.75 \]
**User Interaction:**
Enter your answer in the answer box and then click “Check Answer”.
**User Interface Elements:**
- Several buttons for inserting symbols and mathematical notations.
- Final Check button to validate the entered answer.
**Note to Users:**
All parts of the question are shown, and users should see a progress bar indicating completion status.
**Example Display:**
- The text display includes the genotype information, expected outcomes, probability calculations, and instructions for user input.
- There is no graph or diagram in this example.
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