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According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.142. The probability that a randomly selected person has vision problems is 0.083. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. O B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. O C. Yes, because this is an application of the Addition Rule for Disjoint Events. O D. No, because hearing problems and vision problems are events that are too similar to one another. Next Question

According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.142. The probability that a randomly selected person has vision problems is 0.083. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. O B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. O C. Yes, because this is an application of the Addition Rule for Disjoint Events. O D. No, because hearing problems and vision problems are events that are too similar to one another. Next Question

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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5.2.35 Question Help According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.142. The probability that a randomly selected person has vision problems is 0.083. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. O B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. O C. Yes, because this is an application of the Addition Rule for Disjoint Events. O D. No, because hearing problems and vision problems are events that are too similar to one another. Next Question
Transcribed Image Text:5.2.35 Question Help According to a center for disease control, the probability that a randomly selected person has hearing problems is 0.142. The probability that a randomly selected person has vision problems is 0.083. Can we compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities? Why or why not? Choose the correct answer below. O A. No, because hearing and vision problems are not mutually exclusive. So, some people have both hearing and vision problems. These people would be included twice in the probability. O B. Yes, because hearing and vision are two different senses, and therefore, they are two unique problems. O C. Yes, because this is an application of the Addition Rule for Disjoint Events. O D. No, because hearing problems and vision problems are events that are too similar to one another. Next Question
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