According to TMUSS Quarterly (Totally Made-Up Sports Statistics) April 2017, the probability that the Tampa Bay Buccaneers will score a touchdown on their opening drive is 0.27.  The probability that their defense will have 3 or more sacks in the game is 0.12.  The probability that the Bucs will both score a touchdown on their opening drive and have 3 or more sacks in the game is 0.08.  What is the probability that they will either score a touchdown on the opening drive or have 3 or more sacks in the game?

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According to TMUSS Quarterly (Totally Made-Up Sports Statistics) April 2017, the probability that the Tampa Bay Buccaneers will score a touchdown on their opening drive is 0.27.  The probability that their defense will have 3 or more sacks in the game is 0.12.  The probability that the Bucs will both score a touchdown on their opening drive and have 3 or more sacks in the game is 0.08.  What is the probability that they will either score a touchdown on the opening drive or have 3 or more sacks in the game?

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Step 1

Given data:

 

The given probability that the Tampa Bay Buccaneers score on their opening is P(X)=0.27.

The given probability that the defendant has three or more sacks is P(Y)=0.12.

The probability that the Tampa Bay Buccaneers score on their opening and the defendant has three or more sacks is P(A∩B)=0.08.

 

The expression for the probability the Tampa Bay Buccaneers score on their opening or the defendant has three or more sacks is,

P(XY)=P(X)+P(Y)-P(XY)

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