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Acceleration (v₁ − v¡)

Acceleration (v₁ − v¡)

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Show all work. Acceleration should be negative. Solve for both trains using the best equation from the equation list.

Acceleration a= (vj − v₁) t 1 x = v₁t + = at² 2 Vƒ = V₁ + at v} = v} + 2ax ² = ( 01+07) ₁ t X=
Transcribed Image Text:Acceleration a= (vj − v₁) t 1 x = v₁t + = at² 2 Vƒ = V₁ + at v} = v} + 2ax ² = ( 01+07) ₁ t X=
Judith is overseeing the setting up a dangerous stunt for a movie. The script calls for two trains to travel towards each other at 20 m/s to the right and 20 m/s to the left. The rightwards moving train can slow down with an acceleration of 1 m/s² while the leftwards moving train is limited to a deceleration of 0.5 m/s². The trains will both start to slow down a distance of 800 meters from each other. Without using any equations, Judith predicts that the trains will stop nose to nose 200 meters from the right, and 600 meters from the left. these are numbers you want to compare Is Judith correct about the stopping locations of both trains? a possible goal for this one, is to to calculate the stopping distance of both trains and compare it to the 200 and 600 V₁-20 Vf = 0 -1 or a = -1 ***** or - as
Transcribed Image Text:Judith is overseeing the setting up a dangerous stunt for a movie. The script calls for two trains to travel towards each other at 20 m/s to the right and 20 m/s to the left. The rightwards moving train can slow down with an acceleration of 1 m/s² while the leftwards moving train is limited to a deceleration of 0.5 m/s². The trains will both start to slow down a distance of 800 meters from each other. Without using any equations, Judith predicts that the trains will stop nose to nose 200 meters from the right, and 600 meters from the left. these are numbers you want to compare Is Judith correct about the stopping locations of both trains? a possible goal for this one, is to to calculate the stopping distance of both trains and compare it to the 200 and 600 V₁-20 Vf = 0 -1 or a = -1 ***** or - as
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