**Title: Probability of Companies Receiving a Discount****Scenario Overview:**In a specific region, approximately 5% of hourly paid workers earn the prevailing minimum wage or less. A grocery chain offers discount rates to companies that employ at least 30 workers who fall within this wage bracket. We will determine the probability of three different companies qualifying for this discount.**Company Details and Probability Calculations:**(a) **Company A**- Number of Employees: 295- Task: Calculate the probability that Company A will qualify for the discount.- **Answer:** Provide a detailed calculation here. (Round to four decimal places as needed.)(b) **Company B**- Number of Employees: 547- Task: Calculate the probability that Company B will qualify for the discount.- **Answer:** Provide a detailed calculation here. (Round to four decimal places as needed.)(c) **Company C**- Number of Employees: 1012- Task: Calculate the probability that Company C will qualify for the discount.- **Answer:** Provide a detailed calculation here. (Round to four decimal places as needed.)**Further Explanation:**To solve these probability problems, one should consider using the binomial distribution formula, given the fixed probability of earning minimum wage and the number of trials represented by employees.If needed, include explanations for key concepts such as binomial probability and how to calculate it step-by-step for each company, rounding results to the specified decimal places for precision.

About 5% of hourly paid workers in a region earn the prevailing minimum wage or less.A grocery chain offers discount rates to companies that have at least 30 employees who earn the prevailing minimum wage or less.(a) Company A has 295 employees. Let X be a random variable that indicates the number of employees out of 295 employees who earn the prevailing minimum wage or less.Here X follows binomial distribution with parameters and .Since both and are greater than 5, normal approximation for binomial distribution is valid.Mean is:Standard deviation is:Using continuity correction, required probability is computed as follows:Excel output is shown below:Thus, the probability that Company A will get the discount is 0.0000.(b) Company A has 547 employees. Let X be a random variable that indicates the number of employees out of 547 employees who earn the prevailing minimum wage or less.Here X follows binomial distribution with parameters .Since both and are greater than 5, normal approximation for binomial distribution is valid.Mean is:Standard deviation is:Using continuity correction, required probability is computed as follows:Excel output is shown below:Thus, the probability that Company B will get the discount is 0.3372.(c) Company C has 1012 employees. Let X be a random variable that indicates the number of employees out of 1012 employees who earn the prevailing minimum wage or less.Here X follows binomial distribution with parameters .Since both and are greater than 5, normal approximation for binomial distribution is valid.Mean is:Standard deviation is:Using continuity correction, required probability is computed as follows:Excel output is shown below:Thus, the probability that Company C will get the discount is 0.9988.(a) The probability that Company A will get the discount is 0.0000.(b) The probability that Company B will get the discount is 0.3372.(c) The probability that Company C will get the discount is 0.9988.