Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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ABCD is a square. Find the value of x.
![### Problem Description
ABCD is a square. Find the value of \( x \).
### Diagram Explanation
The diagram represents a square ABCD with lines drawn from corner to corner, forming two diagonals. These diagonals intersect at the center, creating four right-angle triangles within the square. At the intersection point of the diagonals, an angle is marked as \((11x + 35)^\circ\).
### Key Points
- In a square, the diagonals are **perpendicular bisectors** of each other.
- This means they form four right angles (90 degrees) at the intersection.
### Problem Solution
Given that the angle at the intersection of the diagonals is \( (11x + 35)^\circ \):
Since the diagonals are perpendicular, they create a 90-degree angle.
Set the expression equal to 90 degrees:
\[ 11x + 35 = 90 \]
Solve for \( x \):
\[ 11x = 90 - 35 \]
\[ 11x = 55 \]
\[ x = \frac{55}{11} \]
\[ x = 5 \]
Thus, the value of \( x \) is:
\[ x = 5 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c2913e4-3d86-4c39-9afb-ae3f41846d68%2F561f5509-b600-4ec8-b9dc-dc5cd176b68e%2Fm6rg1ho_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Description
ABCD is a square. Find the value of \( x \).
### Diagram Explanation
The diagram represents a square ABCD with lines drawn from corner to corner, forming two diagonals. These diagonals intersect at the center, creating four right-angle triangles within the square. At the intersection point of the diagonals, an angle is marked as \((11x + 35)^\circ\).
### Key Points
- In a square, the diagonals are **perpendicular bisectors** of each other.
- This means they form four right angles (90 degrees) at the intersection.
### Problem Solution
Given that the angle at the intersection of the diagonals is \( (11x + 35)^\circ \):
Since the diagonals are perpendicular, they create a 90-degree angle.
Set the expression equal to 90 degrees:
\[ 11x + 35 = 90 \]
Solve for \( x \):
\[ 11x = 90 - 35 \]
\[ 11x = 55 \]
\[ x = \frac{55}{11} \]
\[ x = 5 \]
Thus, the value of \( x \) is:
\[ x = 5 \]
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