A 73-kg cross-country skier glides over snow as in the figure below. The coefficient of friction between skis and snow is 0.23. Assume all the snow beneath her skis is at 0°C and that all the internal energy generated by friction is added to snow, which sticks to her skis until it melts. How far would she have to ski to melt 2.5 kg of snow? The snow is already at the melting temperature of 0°C so the energy Q that must be added to convert a kilogram of snow into liquid water at 0°C is given by the following equation, where m is the mass to be converted and LF is the latent heat of fusion of water. Q = mLf = (2.5 kg) (3.33 x 10^5 J/kg) = ____________ x 10^5 J
A 73-kg cross-country skier glides over snow as in the figure below. The coefficient of friction between skis and snow is 0.23. Assume all the snow beneath her skis is at 0°C and that all the internal energy generated by friction is added to snow, which sticks to her skis until it melts. How far would she have to ski to melt 2.5 kg of snow? The snow is already at the melting temperature of 0°C so the energy Q that must be added to convert a kilogram of snow into liquid water at 0°C is given by the following equation, where m is the mass to be converted and LF is the latent heat of fusion of water. Q = mLf = (2.5 kg) (3.33 x 10^5 J/kg) = ____________ x 10^5 J
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 73-kg cross-country skier glides over snow as in the figure below. The coefficient of friction between skis and snow is 0.23. Assume all the snow beneath her skis is at 0°C and that all the internal energy generated by friction is added to snow, which sticks to her skis until it melts. How far would she have to ski to melt 2.5 kg of snow?
The snow is already at the melting temperature of 0°C so the energy Q that must be added to convert a kilogram of snow into liquid water at 0°C is given by the following equation, where m is the mass to be converted and LF is the latent heat of fusion of water.
Q | = | mLf |
= (2.5 kg) (3.33 x 10^5 J/kg)
= ____________ x 10^5 J
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