A1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the centerline at a point 1.05 m behind the front axle. Find the force exerted by the ground on each wheel. each front wheel kN each rear wheel kN Need Help? Read It Master It

A1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the centerline at a point 1.05 m behind the front axle. Find the force exerted by the ground on each wheel. each front wheel kN each rear wheel kN Need Help? Read It Master It

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 1 555-kg automobile has a wheel base (the distance between the axles) of l = 2.85 m. The automobile's center of mass is on the centerline at a point 1.35 m behind the front axle. Find the force exerted by the ground on each wheel. Part 1 of 3 - Conceptualize Since the center of mass is located in the front half of the car, there should be more force on the front wheels than the rear ones. The sum of the wheel forces must equal the weight of the car. Part 2 of 3 - Categorize Use the figure as a force diagram. Apply Newton's second law and sum the torques to find the unknown forces. l Part 3 of 3 - Analyze The torque about the front axle is zero, so we have Στις = 0 = (d Fg) - l (2F₁). Thus the force at each rear wheel is given by d F F₁ = 2Ff g || d 21 2F, m)(1. X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step da N. Since the sum of the wheel forces equals the weight of the car, we have 2F₁ + 2F₁ = Fg.…
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