Draw a circuit for the truth table with logic chips 7408, 7432 and 7486 A10000000011111111Ao0。。。。00111100001Inputs111B1 B0 D30110011001100111010110100010100P00o0-00000-01OutputsD2。。00000000110D11O0000110100011108Do0000010100000101

Given Data:A truth table with,Inputs The SOP canonical forms of the output are,To Find:Circuit with…

Answered: A1 0 00 0 0 0 0 0 0 1 1 1 1 1 1 1 1 АО…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Draw a circuit for the truth table with logic chips 7408, 7432 and 7486

A1
0
0
0
0
0
0
0
0
1
1
1
1
1
1
1
1
Ao
0
。。。。
0
0
1
1
1
1
0
0
0
0
1
Inputs
1
1
1
B1 B0 D3
0
1
1
0
0
1
1
0
0
1
1
0
0
1
1
1
0
1
0
1
1
0
1
00
0
1
0
1
0
0
P
0
0
o
0
-
0
0
0
0
0
-
0
1
Outputs
D2
。。
0
0
0
0
0
0
0
0
1
1
0
D1
1
O
0
0
0
0
1
1
0
1
00
0
1
1
1
0
8
Do
0
0
0
0
0
1
0
1
0
0
0
0
0
1
0
1

Expert Solution

Step 1: Summarize the details given:

Given Data:

A truth table with,

Inputs $open parentheses A subscript 1 A subscript 0 B subscript 1 B subscript 0 close parentheses$
The SOP canonical forms of the output are,
- $D subscript 3 equals sum for blank of m open parentheses 15 close parentheses$
- $D subscript 2 equals sum for blank of m open parentheses 10 comma space 11 comma space 14 close parentheses$
- $D subscript 1 equals sum for blank of m open parentheses 6 comma space 7 comma space 9 comma space 11 comma space 13 comma space 14 close parentheses$
- $D subscript 0 equals sum for blank of m open parentheses 5 comma space 7 comma space 13 comma space 15 close parentheses$

To Find:

Circuit with the logic chips 7408 (AND) , 7432 (OR) and 7486 (XOR)

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