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A1 0 00 0 0 0 0 0 0 1 1 1 1 1 1 1 1 АО 0 0 0 1 1 1 1 0 0 0 0 1 1 Inputs 1 1 B1 00 0 1 1 0 0 1 1 0 0 1 1 0 0 1 Bo 1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 D3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 Outputs D2 0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 0 D1 0 0 0 0 0 0 1 1 0 1 0 1 0 1 1 0 DO 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1

A1 0 00 0 0 0 0 0 0 1 1 1 1 1 1 1 1 АО 0 0 0 1 1 1 1 0 0 0 0 1 1 Inputs 1 1 B1 00 0 1 1 0 0 1 1 0 0 1 1 0 0 1 Bo 1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 D3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 Outputs D2 0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 0 D1 0 0 0 0 0 0 1 1 0 1 0 1 0 1 1 0 DO 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question

Draw a circuit for the truth table with logic chips 7408, 7432 and 7486

A1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 Ao 0 。。。。 0 0 1 1 1 1 0 0 0 0 1 Inputs 1 1 1 B1 B0 D3 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 00 0 1 0 1 0 0 P 0 0 o 0 - 0 0 0 0 0 - 0 1 Outputs D2 。。 0 0 0 0 0 0 0 0 1 1 0 D1 1 O 0 0 0 0 1 1 0 1 00 0 1 1 1 0 8 Do 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1
Transcribed Image Text:A1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 Ao 0 。。。。 0 0 1 1 1 1 0 0 0 0 1 Inputs 1 1 1 B1 B0 D3 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 00 0 1 0 1 0 0 P 0 0 o 0 - 0 0 0 0 0 - 0 1 Outputs D2 。。 0 0 0 0 0 0 0 0 1 1 0 D1 1 O 0 0 0 0 1 1 0 1 00 0 1 1 1 0 8 Do 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1
Expert Solution
Step 1: Summarize the details given:

Given Data:

A truth table with,

  • Inputs open parentheses A subscript 1 A subscript 0 B subscript 1 B subscript 0 close parentheses
  • The SOP canonical forms of the output are,
    • D subscript 3 equals sum for blank of m open parentheses 15 close parentheses
    • D subscript 2 equals sum for blank of m open parentheses 10 comma space 11 comma space 14 close parentheses
    • D subscript 1 equals sum for blank of m open parentheses 6 comma space 7 comma space 9 comma space 11 comma space 13 comma space 14 close parentheses
    • D subscript 0 equals sum for blank of m open parentheses 5 comma space 7 comma space 13 comma space 15 close parentheses

To Find:

Circuit with the logic chips 7408 (AND) , 7432 (OR) and 7486 (XOR)

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