A0.493 M aqueous solution of a non-electrolyte has a density of 1.063 g/mL, and a freezing point of -1.03 °C. What is the molar mass of the compound?

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A0.493 M aqueous solution of a non-electrolyte has a density of 1.063 g/mL, and a
freezing point of -1.03 °C. What is the molar mass of the compound?
Transcribed Image Text:A0.493 M aqueous solution of a non-electrolyte has a density of 1.063 g/mL, and a freezing point of -1.03 °C. What is the molar mass of the compound?
Expert Solution
Step 1

Colligative properties are the properties which depend on the number of atoms or molecules or ions or particles present in the solution. Some common colligative properties are depression in freezing point, elevation in boiling point, osmotic pressure and relative lowering in vapor pressure.

Step 2

Depression in freezing point is a colligative property that can be calculated with the help of concentration (molality) of solution. The relation between depression in freezing point and molality of solution can be written as:'Chemistry homework question answer, step 2, image 1

Here:

ΔTf= elevation in boiling point

kf= Molal depression constant for freezing point

i = van’t Hoff factor (depends on number of ions formed after dissociation)

m= molality (moles of solute / mass of solvent in kg)

Step 3

Molarity of solution = 0.493 M

Thus moles of solute = 0.493 moles

Volume of solution = 1 L = 1000 mL

Density of solution= 1.063 g/mL

Calculate mass of solution:

Chemistry homework question answer, step 3, image 1

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