The freezing point of ethanol, CH3CH₂OH, is -117.300 °C at 1 atmosphere. K(ethanol) = 1.99 °C/m In a laboratory experiment, students synthesized a new compound and found that when 10.78 grams of the compound were dissolved in 294.9 grams of ethanol, the solution began to freeze at -117.697 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound? g/mol

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The freezing point of ethanol, CH3CH₂OH, is -117.300 °C at 1 atmosphere. Kethanol) = 1.99 °C/m
In a laboratory experiment, students synthesized a new compound and found that when 10.78 grams of the compound were
dissolved in 294.9 grams of ethanol, the solution began to freeze at -117.697 °C. The compound was also found to be
nonvolatile and a non-electrolyte.
What is the molecular weight they determined for this compound?
g/mol
Transcribed Image Text:The freezing point of ethanol, CH3CH₂OH, is -117.300 °C at 1 atmosphere. Kethanol) = 1.99 °C/m In a laboratory experiment, students synthesized a new compound and found that when 10.78 grams of the compound were dissolved in 294.9 grams of ethanol, the solution began to freeze at -117.697 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound? g/mol
Expert Solution
Step 1: Given data

Given:

Mass of solute = 10.78 g

Mass of solvent ethanol = 294.9 g

The solution began to freeze at  -117.697oC

Freezing point of pure solvent ethanol = -117.300oC

K= 1.99oC/m

This is an example of depression in the freezing point experiment. When a non-volatile solute is added to a pure solvent, there is a decrease in the freezing point of the solvent. That means the freezing point of the solution is less than the freezing point of the solvent. This is known as the depression in the freezing point. Depression in the freezing point is a colligative property.

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