a. Write a function countBits(int) that counts the number of bits that are 1. For example countBits(9) should return 2 because 9 = 1001 while countBits(16) should return 1 (10000 has one 1-bit).
a. Write a function countBits(int) that counts the number of bits that are 1. For example countBits(9) should return 2 because 9 = 1001 while countBits(16) should return 1 (10000 has one 1-bit).
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![Computation
a. Write a function countBits(int) that counts the number of bits that are 1. For example
countBits(9) should return 2 because 9 = 1001 while countBits(16) should return 1
(10000 has one 1-bit).
b. Write a function polynomial that takes an array of double, a length, and x as shown:
double c[] = {3.0, 1.5, 1.0, -2.5);
double y = polynomial(c, 4, 2.0);
should compute the polynomial 3.0x + 1.5x² + 1.0x - 2.5
Note that the efficient way to do this is Horner's form:
((3.0 * x + 1.5) * x+ 1.0) * x - 2.5
You must use a loop, not hardcode it. Your code should work for.
double c[] = {5.0, 1.0, 2.0, 3.5, 5.2};
cout << polynomial(c, 5. 2.2):
c. Given the following 2-dimensional matrix, write loops to print out the sum of every row
then column:
constexpr int rows = 3, cols = 4;
double x[rows][cols)] = {
{1, 2, 3.5},
(2. -1, 1.5}
}:
Your loop should compute 1+2+3.5 = 6.5 and 2-1+1.5 = 2.5 for the two rows, then for the
columns: 1+2 = 3, 2-1 = 1, and 3.5+1.5 = 5.
The output of the program should be:
6.5 2.5
315
d. Write a template function that sums and prints out the arrays in the following main:
int main() {
string a[] = {"yo", "ho"};
int b[] = {1, 2, 3}:
cout << sum(a, 2) << 'n';
cout << sum(b, 3) < 'n';
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbcfb8dea-921b-49cc-9763-7233db60feda%2F3c326b93-0ef9-4bbd-a841-3019a96a15e0%2F7idcqkb_processed.png&w=3840&q=75)
Transcribed Image Text:Computation
a. Write a function countBits(int) that counts the number of bits that are 1. For example
countBits(9) should return 2 because 9 = 1001 while countBits(16) should return 1
(10000 has one 1-bit).
b. Write a function polynomial that takes an array of double, a length, and x as shown:
double c[] = {3.0, 1.5, 1.0, -2.5);
double y = polynomial(c, 4, 2.0);
should compute the polynomial 3.0x + 1.5x² + 1.0x - 2.5
Note that the efficient way to do this is Horner's form:
((3.0 * x + 1.5) * x+ 1.0) * x - 2.5
You must use a loop, not hardcode it. Your code should work for.
double c[] = {5.0, 1.0, 2.0, 3.5, 5.2};
cout << polynomial(c, 5. 2.2):
c. Given the following 2-dimensional matrix, write loops to print out the sum of every row
then column:
constexpr int rows = 3, cols = 4;
double x[rows][cols)] = {
{1, 2, 3.5},
(2. -1, 1.5}
}:
Your loop should compute 1+2+3.5 = 6.5 and 2-1+1.5 = 2.5 for the two rows, then for the
columns: 1+2 = 3, 2-1 = 1, and 3.5+1.5 = 5.
The output of the program should be:
6.5 2.5
315
d. Write a template function that sums and prints out the arrays in the following main:
int main() {
string a[] = {"yo", "ho"};
int b[] = {1, 2, 3}:
cout << sum(a, 2) << 'n';
cout << sum(b, 3) < 'n';
}
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