a. Show that |X — х У1 - у Z1 X2 - x Z2 - z = 0 Y2 - y |Xз — х Уз — у 23 — is an equation for the plane through the three noncollinear points P,(x1, y1, Z1), P2(x2, Y2, Z2), and P3(x3, y3, Z3).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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a. Show that
|X — х У1 - у
Z1
X2 - x
Z2 - z = 0
Y2 - y
|Xз — х Уз — у 23 —
is an equation for the plane through the three noncollinear
points P,(x1, y1, Z1), P2(x2, Y2, Z2), and P3(x3, y3, Z3).
Transcribed Image Text:a. Show that |X — х У1 - у Z1 X2 - x Z2 - z = 0 Y2 - y |Xз — х Уз — у 23 — is an equation for the plane through the three noncollinear points P,(x1, y1, Z1), P2(x2, Y2, Z2), and P3(x3, y3, Z3).
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