A. Rearrange the data in step 1c. from highest to lowest numbers. (Put a space between each pairs of numbers.) B. Label the Parentals (= the pair of numbers that are the most frequent) versus Recombinants. C. Further subdivide recombinants as single crossovers region 1", single crossovers region 2*, double crossovers (-least frequent). [*note: single cross overs are the two pairs that are intermediate between parentals and double cross overs.] and

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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A. Rearrange the data in step 1c. from highest to lowest numbers. (Put a space between each
pairs of numbers.)
B. Label the Parentals (= the pair of numbers that are the most frequent) versus Recombinants.
C. Further subdivide recombinants as single crossovers region 1", single crossovers region 2*, and
double crossovers (-least frequent). [*note: single cross overs are the two pairs that are
intermediate between parentals and double cross overs.]
Transcribed Image Text:A. Rearrange the data in step 1c. from highest to lowest numbers. (Put a space between each pairs of numbers.) B. Label the Parentals (= the pair of numbers that are the most frequent) versus Recombinants. C. Further subdivide recombinants as single crossovers region 1", single crossovers region 2*, and double crossovers (-least frequent). [*note: single cross overs are the two pairs that are intermediate between parentals and double cross overs.]
Copyright © 201
Virtual Coursewa
ses
Analyze Lab Notes
Include a test of hypothesis
e sex of flies
Results for Cross #2
Observed
Proportion
Phenotype
423
0.4226
0.0060
PR
50
0.0500
VG
29
0.0290
BL
17
0.0170
PR. VG
PR. BL
59
0.0589
V.G. BL
3.
0.0030
P.R.V.G. BL
414
0.4136
Total
1001
1.0000
Mapping Ex....docx
Transcribed Image Text:Copyright © 201 Virtual Coursewa ses Analyze Lab Notes Include a test of hypothesis e sex of flies Results for Cross #2 Observed Proportion Phenotype 423 0.4226 0.0060 PR 50 0.0500 VG 29 0.0290 BL 17 0.0170 PR. VG PR. BL 59 0.0589 V.G. BL 3. 0.0030 P.R.V.G. BL 414 0.4136 Total 1001 1.0000 Mapping Ex....docx
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