а. PClis(9) + C2 (9) — PCI5(9) с. Hа(9) + Br2(9) — 2 НBr(g) b. 2 SO2(g) + O2(g) 2 SO3(g) d. CH,(g) + 3 Cl,(9) = CHCI3(g) + 3 HCI(g)

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.94QP
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Write the expression for the equilibrium constant for each equation.

а. PClis(9) + C2 (9) —
PCI5(9)
с. Hа(9) + Br2(9) — 2 НBr(g)
b. 2 SO2(g) + O2(g) 2 SO3(g)
d. CH,(g) + 3 Cl,(9) =
CHCI3(g) + 3 HCI(g)
Transcribed Image Text:а. PClis(9) + C2 (9) — PCI5(9) с. Hа(9) + Br2(9) — 2 НBr(g) b. 2 SO2(g) + O2(g) 2 SO3(g) d. CH,(g) + 3 Cl,(9) = CHCI3(g) + 3 HCI(g)
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